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xRAWRRx3

  • 2 years ago

Please help :( The lengths of two of the sides of a certain triangle are (x - 3) and (x+3) where x > 3. Which of the following ranges represent all of the possible values of the third side, s?

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  1. PaxPolaris
    • 2 years ago
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    The sum of any two side of a triangle have to be greater than the third side.

  2. PaxPolaris
    • 2 years ago
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    So, \[\large(x-3)+(x+3) >s\]\[\large(x-3)+s >(x+3)\]\[\large\cancel{(x+3)+s >(x-3)}\] use the first two inequalities to find the limit for s

  3. xRAWRRx3
    • 2 years ago
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    why not the last one? does it cancel out or something?

  4. PaxPolaris
    • 2 years ago
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    we already know that \(x+3>x−3\) .... so the last one happens to be true for all s ... it doesn't help

  5. xRAWRRx3
    • 2 years ago
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    ohh, okay. So would the answer be 6 < s < 2x ?

  6. PaxPolaris
    • 2 years ago
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    yes \(\Large\checkmark\)

  7. xRAWRRx3
    • 2 years ago
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    Thank you so much :) I really didn't know what to do for it so you helped me SO much :)

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