anonymous
  • anonymous
Please help :( In the figure below, triangle TED in rectangle TBCD is equilateral. If TB = 10, to the nearest hundredth, what is the length of ED?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1338703391644:dw|
jim_thompson5910
  • jim_thompson5910
Are you familiar with any trig?
anonymous
  • anonymous
well, a little bit.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
hmm then again, you said geometry, so let me think of a way to do it without trig
anonymous
  • anonymous
no no, you can use a bit of trig if it is simple :)
jim_thompson5910
  • jim_thompson5910
Step 1) Label the length of ED x. So TE = x and TD = x as well since we're dealing with an equilateral triangle |dw:1338704023305:dw|
jim_thompson5910
  • jim_thompson5910
Step 2) Cut TD in half. Label the midpoint of TD point F and draw the segment EF |dw:1338704102241:dw|
jim_thompson5910
  • jim_thompson5910
The length of TF and FD are x/2 since we've cut TD = x in half
jim_thompson5910
  • jim_thompson5910
FE = TB, so FE = 10
jim_thompson5910
  • jim_thompson5910
So we have the following |dw:1338704182291:dw|
jim_thompson5910
  • jim_thompson5910
Since we have the right triangle EFD, we can say EF^2 + FD^2 = ED^2 but we know that EF = 10, FD = x/2 and ED = x, so... 10^2 + (x/2)^2 = x^2 100 + x^2/4 = x^2 400 + x^2 = 4x^2 400 = 4x^2 - x^2 400 = 3x^2 3x^2 = 400 x^2 = 400/3 x = sqrt(400/3) x = 20/sqrt(3) x = 20*sqrt(3)/3 So the exact length of ED is 20*sqrt(3)/3 units.
jim_thompson5910
  • jim_thompson5910
After that, use a calculator to get 20*sqrt(3)/3 = (20*1.73205)/3 = 34.641/3 = 11.547 Giving us that ED is approximately 11.547 units, which rounds to 11.55
anonymous
  • anonymous
thank you so much x) you really helped me x)
jim_thompson5910
  • jim_thompson5910
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.