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Please help :( Given: Circle O with tangent PA , secant PBC, diameter DOE, and chord AC. PA = 20, PB = 8, AF = CF, measure angle APC = 49, and measure of arc AB = 41. Please help me find the measure of angle COD.
are the angle measure and arc measures are in degrees?
Angle AOB = 41 degrees angle AOC = 180 - 41 degrees = 139 degrees (adj. angles on st. line) Since AF = FC . OD is perpendicular to AC (line joining from centre perpendicular to chord bisects chord) and triangle AOC is an isos triangle angle AOD = angle DOC = angle AOC / 2 = 139/2 = ... ?
69.5??? |dw:1338706212875:dw|
i'll give you hints : (altough i find some info to be useless in the ques) use these things : 1)join OA 2) if a line from the center bisects a chord,that line is perpendicular to the chord 3)a perpendicular to the opposite side in an isosceles triangle bisects the angle in between 4)tangent and radius are perpendicular 5)sum of angles in a triangle = 180 6)sum of linear angles =180 you should get your ans then..
hmmn..@dpaInc already solved it !!
yeahh, pretty much. But thanks, everyone, for helping me x) You all helped me understand the problem a little bit more so thank you x)
I wish I can give medals to you all but sadly, I can't :(
no...it was @Callisto ... :) wish i could take credit though...
You guys make it too.... complicated :|
:) that's what we do....
oh yes..i missed @Callisto post...hmnn..