anonymous
  • anonymous
Use Cramer's Rule to solve the system or to determine that the system is inconsistent or contains dependent equations. 2x + 4y = 12 3x + y = -2 1) inconsistent system 2) {(-2,4)} 3) {(-4, -2)} 4) {(4, -2)}
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

ash2326
  • ash2326
@Audrae_World do you know cramer's rule?
anonymous
  • anonymous
x + y + z = x – y – z = 0 x + 2y + z = 0
ash2326
  • ash2326
That's not Cramer's rule Suppose I have the following system of equations \[a1x+b1y=c1\] and \[a2x+b2y=c2\] Then x and y are given as \[x=\frac{\left[\begin{matrix}c1 & a1 \\ c2& a2\end{matrix}\right]}{\left[\begin{matrix}a1 & b1 \\ a2& b2\end{matrix}\right]}\] \[y=\frac{\left[\begin{matrix}b1 & c1 \\ b2& c2\end{matrix}\right]}{\left[\begin{matrix}a1 & b1 \\ a2& b2\end{matrix}\right]}\] All are determinants, can you find x and y?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
WOAH my teacher didn't teach or classify with my class D:
ash2326
  • ash2326
Do you know determinants ?
anonymous
  • anonymous
determinants like this: [a b c d] and you multiply ad -bc?
ash2326
  • ash2326
Yeah you're right, try this here
anonymous
  • anonymous
Okay thanks :D
ash2326
  • ash2326
Can you do it here? Did you understand?
amistre64
  • amistre64
I think later on the cramer is refered to as the wronskian

Looking for something else?

Not the answer you are looking for? Search for more explanations.