A floor has two square-shaped designs. The area of the second square-shaped design is sixteen times greater than the area of the first square-shaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?

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A floor has two square-shaped designs. The area of the second square-shaped design is sixteen times greater than the area of the first square-shaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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if A and B are the areas of the two squares with A being the bigger square And, a^2 = A b^2 = B Then, A = 16B => sqrt(A) = sqrt(16B) a = 4b Hope that answers your question!
I think I got it. Would the answer be, "The length of the side of the second square is 8 times greater than the length of the side of the first square."?
Am! That would be 4 times, I think. That's why when we calculate the area (since we square the length of one side), 4 times 4 becomes 16. to if length1 = 4*length2 that implies that: area1 = 16*area2

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two floors consider a & b now b=16a area of square = side square so side b = sqrt b and side a=sqrt 16a =4 sqrt a so 4a =b

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