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jzm1
 3 years ago
A floor has two squareshaped designs. The area of the second squareshaped design is sixteen times greater than the area of the first squareshaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?
jzm1
 3 years ago
A floor has two squareshaped designs. The area of the second squareshaped design is sixteen times greater than the area of the first squareshaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?

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azka.niazi
 3 years ago
Best ResponseYou've already chosen the best response.2if A and B are the areas of the two squares with A being the bigger square And, a^2 = A b^2 = B Then, A = 16B => sqrt(A) = sqrt(16B) a = 4b Hope that answers your question!

jzm1
 3 years ago
Best ResponseYou've already chosen the best response.0I think I got it. Would the answer be, "The length of the side of the second square is 8 times greater than the length of the side of the first square."?

azka.niazi
 3 years ago
Best ResponseYou've already chosen the best response.2Am! That would be 4 times, I think. That's why when we calculate the area (since we square the length of one side), 4 times 4 becomes 16. to if length1 = 4*length2 that implies that: area1 = 16*area2

ajaykharabe
 3 years ago
Best ResponseYou've already chosen the best response.0two floors consider a & b now b=16a area of square = side square so side b = sqrt b and side a=sqrt 16a =4 sqrt a so 4a =b
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