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A floor has two squareshaped designs. The area of the second squareshaped design is sixteen times greater than the area of the first squareshaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?
 one year ago
 one year ago
A floor has two squareshaped designs. The area of the second squareshaped design is sixteen times greater than the area of the first squareshaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?
 one year ago
 one year ago

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azka.niaziBest ResponseYou've already chosen the best response.2
if A and B are the areas of the two squares with A being the bigger square And, a^2 = A b^2 = B Then, A = 16B => sqrt(A) = sqrt(16B) a = 4b Hope that answers your question!
 one year ago

jzm1Best ResponseYou've already chosen the best response.0
I think I got it. Would the answer be, "The length of the side of the second square is 8 times greater than the length of the side of the first square."?
 one year ago

azka.niaziBest ResponseYou've already chosen the best response.2
Am! That would be 4 times, I think. That's why when we calculate the area (since we square the length of one side), 4 times 4 becomes 16. to if length1 = 4*length2 that implies that: area1 = 16*area2
 one year ago

ajaykharabeBest ResponseYou've already chosen the best response.0
two floors consider a & b now b=16a area of square = side square so side b = sqrt b and side a=sqrt 16a =4 sqrt a so 4a =b
 one year ago
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