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mmkoscielski
 2 years ago
Best ResponseYou've already chosen the best response.0would it be cscx^2

BTaylor
 2 years ago
Best ResponseYou've already chosen the best response.0it would be \[\csc^{2} x\]

nolastudent
 2 years ago
Best ResponseYou've already chosen the best response.2(csc x1)(csc x+1) = \[\csc^{2}(x)  1 = (blank)^{2}\] so \[\sqrt{\csc2(x)−1} = blank\]

gandalfwiz
 2 years ago
Best ResponseYou've already chosen the best response.0Nolastudent you're way makes sense, but is there a way to simplify is more?

nolastudent
 2 years ago
Best ResponseYou've already chosen the best response.2yes, sorry, trig identity: csc^2(x)1 = cot^2(x)

nolastudent
 2 years ago
Best ResponseYou've already chosen the best response.2so square root of cotangent squared, which is cotangent.

nolastudent
 2 years ago
Best ResponseYou've already chosen the best response.2That's okay, we're in the math section XD

gandalfwiz
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, that makes more sense. I can never simplify mine enough... :)

nolastudent
 2 years ago
Best ResponseYou've already chosen the best response.2LOL, thanks for the help gandalfwiz!

gandalfwiz
 2 years ago
Best ResponseYou've already chosen the best response.0So the final answer is cotx?
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