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mmkoscielski

  • 3 years ago

(__)^2= (csc x-1)(csc x+1) solve for the blank

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  1. mmkoscielski
    • 3 years ago
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    would it be cscx^2

  2. BTaylor
    • 3 years ago
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    it would be \[\csc^{2} x\]

  3. mmkoscielski
    • 3 years ago
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    okay

  4. nolastudent
    • 3 years ago
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    (csc x-1)(csc x+1) = \[\csc^{2}(x) - 1 = (blank)^{2}\] so \[\sqrt{\csc2(x)−1} = blank\]

  5. gandalfwiz
    • 3 years ago
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    Nolastudent-- you're way makes sense, but is there a way to simplify is more?

  6. nolastudent
    • 3 years ago
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    yes, sorry, trig identity: csc^2(x)-1 = cot^2(x)

  7. gandalfwiz
    • 3 years ago
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    *your*. Sorry... :)

  8. nolastudent
    • 3 years ago
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    so square root of cotangent squared, which is cotangent.

  9. nolastudent
    • 3 years ago
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    That's okay, we're in the math section XD

  10. gandalfwiz
    • 3 years ago
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    Okay, that makes more sense. I can never simplify mine enough... :)

  11. nolastudent
    • 3 years ago
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    LOL, thanks for the help gandalfwiz!

  12. gandalfwiz
    • 3 years ago
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    So the final answer is cotx?

  13. nolastudent
    • 3 years ago
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    yep

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