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anonymous
 4 years ago
(__)^2= (csc x1)(csc x+1) solve for the blank
anonymous
 4 years ago
(__)^2= (csc x1)(csc x+1) solve for the blank

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BTaylor
 4 years ago
Best ResponseYou've already chosen the best response.0it would be \[\csc^{2} x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.1(csc x1)(csc x+1) = \[\csc^{2}(x)  1 = (blank)^{2}\] so \[\sqrt{\csc2(x)−1} = blank\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.1Nolastudent you're way makes sense, but is there a way to simplify is more?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.1yes, sorry, trig identity: csc^2(x)1 = cot^2(x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.1so square root of cotangent squared, which is cotangent.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.1That's okay, we're in the math section XD

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.1Okay, that makes more sense. I can never simplify mine enough... :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.1LOL, thanks for the help gandalfwiz!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.1So the final answer is cotx?
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