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mmkoscielskiBest ResponseYou've already chosen the best response.0
would it be cscx^2
 one year ago

BTaylorBest ResponseYou've already chosen the best response.0
it would be \[\csc^{2} x\]
 one year ago

nolastudentBest ResponseYou've already chosen the best response.2
(csc x1)(csc x+1) = \[\csc^{2}(x)  1 = (blank)^{2}\] so \[\sqrt{\csc2(x)−1} = blank\]
 one year ago

gandalfwizBest ResponseYou've already chosen the best response.0
Nolastudent you're way makes sense, but is there a way to simplify is more?
 one year ago

nolastudentBest ResponseYou've already chosen the best response.2
yes, sorry, trig identity: csc^2(x)1 = cot^2(x)
 one year ago

gandalfwizBest ResponseYou've already chosen the best response.0
*your*. Sorry... :)
 one year ago

nolastudentBest ResponseYou've already chosen the best response.2
so square root of cotangent squared, which is cotangent.
 one year ago

nolastudentBest ResponseYou've already chosen the best response.2
That's okay, we're in the math section XD
 one year ago

gandalfwizBest ResponseYou've already chosen the best response.0
Okay, that makes more sense. I can never simplify mine enough... :)
 one year ago

nolastudentBest ResponseYou've already chosen the best response.2
LOL, thanks for the help gandalfwiz!
 one year ago

gandalfwizBest ResponseYou've already chosen the best response.0
So the final answer is cotx?
 one year ago
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