anonymous
  • anonymous
(__)^2= (csc x-1)(csc x+1) solve for the blank
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
would it be cscx^2
BTaylor
  • BTaylor
it would be \[\csc^{2} x\]
anonymous
  • anonymous
okay

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anonymous
  • anonymous
(csc x-1)(csc x+1) = \[\csc^{2}(x) - 1 = (blank)^{2}\] so \[\sqrt{\csc2(x)−1} = blank\]
anonymous
  • anonymous
Nolastudent-- you're way makes sense, but is there a way to simplify is more?
anonymous
  • anonymous
yes, sorry, trig identity: csc^2(x)-1 = cot^2(x)
anonymous
  • anonymous
*your*. Sorry... :)
anonymous
  • anonymous
so square root of cotangent squared, which is cotangent.
anonymous
  • anonymous
That's okay, we're in the math section XD
anonymous
  • anonymous
Okay, that makes more sense. I can never simplify mine enough... :)
anonymous
  • anonymous
LOL, thanks for the help gandalfwiz!
anonymous
  • anonymous
So the final answer is cotx?
anonymous
  • anonymous
yep

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