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mmkoscielski Group TitleBest ResponseYou've already chosen the best response.0
would it be cscx^2
 2 years ago

BTaylor Group TitleBest ResponseYou've already chosen the best response.0
it would be \[\csc^{2} x\]
 2 years ago

nolastudent Group TitleBest ResponseYou've already chosen the best response.2
(csc x1)(csc x+1) = \[\csc^{2}(x)  1 = (blank)^{2}\] so \[\sqrt{\csc2(x)−1} = blank\]
 2 years ago

gandalfwiz Group TitleBest ResponseYou've already chosen the best response.0
Nolastudent you're way makes sense, but is there a way to simplify is more?
 2 years ago

nolastudent Group TitleBest ResponseYou've already chosen the best response.2
yes, sorry, trig identity: csc^2(x)1 = cot^2(x)
 2 years ago

gandalfwiz Group TitleBest ResponseYou've already chosen the best response.0
*your*. Sorry... :)
 2 years ago

nolastudent Group TitleBest ResponseYou've already chosen the best response.2
so square root of cotangent squared, which is cotangent.
 2 years ago

nolastudent Group TitleBest ResponseYou've already chosen the best response.2
That's okay, we're in the math section XD
 2 years ago

gandalfwiz Group TitleBest ResponseYou've already chosen the best response.0
Okay, that makes more sense. I can never simplify mine enough... :)
 2 years ago

nolastudent Group TitleBest ResponseYou've already chosen the best response.2
LOL, thanks for the help gandalfwiz!
 2 years ago

gandalfwiz Group TitleBest ResponseYou've already chosen the best response.0
So the final answer is cotx?
 2 years ago
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