anonymous
  • anonymous
1.) Solve the following system of equations. 3x - 2y = 6 6x - 4y = 14 (0, 0) (6, 14) Infinitely Many Solutions No Solutions 2.) What is the value of the y variable in the solution to the following system of equations? 5x + 4y = 1 4x + 3y = -1 -7 7 9 -9 3.) Which point lies in the solution set for the following system of inequalities? y < 2x + 4 y < -2x + 2 (1, 0) (-5, -2) (0, -3) (-1, 5) Please try to help. Any help from anyone is appreciated...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Tennistar
  • Tennistar
hold on , will get the answer
Tennistar
  • Tennistar
-x=24 x=-24 -72-6y=12 -6y=84 y=-14 3x-2y=6 6x-4y=12 2(3x-2y=6) 6x-4y=12 6x-4y=12 infinitely many solutions
Tennistar
  • Tennistar
Q1

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More answers

anonymous
  • anonymous
1. 3x_2y=6 6x-4y=14 multiply first equation with -2 0x+0y=2 then no solutions
anonymous
  • anonymous
Uh, 2 answers for question 1... very confusing, but okay.
aroub
  • aroub
The third answer for question 1!
aroub
  • aroub
-2(3x-2y=6) 6x-4y=14 => -6x+4y=-12 6x-4y=14 ----------- 0=2 So yeah strenesmee is right :)
anonymous
  • anonymous
Alright then...
aroub
  • aroub
2.) 5x + 4y = 1 4x + 3y = -1 -3(5x+4y=1) 4(4x+3y=-1) => -15x-12y=-3 16x+12y=-4 -------------- x=-7 substitute x in any of the equations to find y: 4(-7)+3y=-1 -28+3y=-1 3y=27 y=9
aroub
  • aroub
Any doubts?
anonymous
  • anonymous
Nope, none at all ^_^
aroub
  • aroub
=D
anonymous
  • anonymous
Would you happen to know anything about the last question on here? ----^
aroub
  • aroub
Oh, the third question is graphing x_x
anonymous
  • anonymous
If you can;t get it, it's fine. I'm thankful for all the help you've already given me :)
aroub
  • aroub
Umm, no it's okay. I'm going to try to graph it here.
aroub
  • aroub
|dw:1338838770642:dw| 3.) y < 2x + 4 y < -2x + 2 For every inequality there is an associated equation for it. y < 2x + 4 = y=2x+4 => (0,4) and (-2,0) y < -2x + 2 = y=-2x+2 => (0,2) and (1,0)
aroub
  • aroub
So the answer is ( 0,-3)
anonymous
  • anonymous
Okay, thank you so much! :D
aroub
  • aroub
No problemooo! =D

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