anonymous
  • anonymous
Please help me.... Solve for x in the figure...
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
i need a verification of the answer...
phi
  • phi
|dw:1338841363176:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

phi
  • phi
so (9+7)7= (x+8)8 112-64=8x x= 6
anonymous
  • anonymous
awesome, @phi , thanks....:) i knew i wasn't going crazy!
phi
  • phi
I take it you are getting bogus answers from your answer key?
anonymous
  • anonymous
@AcidRa1n , here it is.... no, someone was challenging my answer/solution...
anonymous
  • anonymous
thanks again...:)
anonymous
  • anonymous
LOL I know it was right dpalnc.. I would second guess your answer it was just my teacher ima yell at him
anonymous
  • anonymous
give me his email... i'll give him a headlock!
anonymous
  • anonymous
lol!
anonymous
  • anonymous
satisfied?
anonymous
  • anonymous
gonna close it...
anonymous
  • anonymous
yeah man
anonymous
  • anonymous
ok...:)
anonymous
  • anonymous
wait!
anonymous
  • anonymous
I was doing some research on TED I really like him lol..

Looking for something else?

Not the answer you are looking for? Search for more explanations.