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The figure below shows AB = 3 units and BD = 4 units. If the area of triangle ADE is 60 square units, what is the area of the trapezoid BCED? (4 points) 11.02 square units 24.56 square units 48.98 square units 53.84 square units

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@AccessDenied Do you mind looking at this quickly?
It looks to me like you should find the similarity ratio / area ratio between the two triangles and find the area of the smaller triangle. Then, subtract the smaller triangle's area from the larger triangle's area, which will just leave the trapezoid's area.

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Is it C? I'm still a bit confused.
Well, how did you get C?
C is correct, just curious what you're confused on tho.
We have two similar triangles (the three angles are congruent so by definition they are similar). So, we can use their similarity ratio: 3:(3+4) = 3:7 and then find the area ratio (a:b)^2 9:49 To find the area of the smaller triangle by creating a proportion. \[ \frac{9}{49} = \frac{x}{60} \] This proportion comes from the idea that their areas will always simplify to this ratio. So, we can solve for x here by cross-multiplying and then dividing off the 49. From there, we just have to subtract off from 60 (the value of x (the smaller area) and we will get the area of the remaining part: |dw:1338850192482:dw|
Okay! I understand it now. Thanks so much!
You're welcome. :)

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