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liliy

  • 3 years ago

MATRIX: solve for x's:

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  1. javawarrior
    • 3 years ago
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    wheres my matrix?

  2. liliy
    • 3 years ago
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    im drawing it

  3. liliy
    • 3 years ago
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    2a -6c=-8 b+2c=3 3a+6b-2c=-4

  4. liliy
    • 3 years ago
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    i changed the x's to a,b,c so its easier:)PLZ HELP!!!

  5. javawarrior
    • 3 years ago
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    are you familiar with row operations?

  6. liliy
    • 3 years ago
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    ya

  7. javawarrior
    • 3 years ago
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    this what your matrix should look like

  8. liliy
    • 3 years ago
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    i did it but i wanna make sure i got the right answers

  9. javawarrior
    • 3 years ago
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    | 1 0 0 | 19.6 | | 0 1 0 | -7.4 | | 0 0 1 | 5.2 __|

  10. javawarrior
    • 3 years ago
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    what i got

  11. liliy
    • 3 years ago
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    :(

  12. liliy
    • 3 years ago
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    a=2 b=-1 c=2

  13. javawarrior
    • 3 years ago
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    wait for some one else to solve it, i could be wrong :)

  14. javawarrior
    • 3 years ago
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    if you substitute back my answers into the equations they work, so its right.

  15. liliy
    • 3 years ago
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    aight. i give up:(

  16. phi
    • 3 years ago
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    If we start with this matrix 2 0 -6 -8 <--- divide this row by 2 to simplify it 0 1 2 3 3 6 -2 -4 1 0 -3 -4 <--- multiply this row by -3 and add to the 3rd row 0 1 2 3 3 6 -2 -4 1 0 -3 -4 0 1 2 3 0 6 7 8 <--- we added -3 0 9 12 to the 3rd row 1 0 -3 -4 0 1 2 3<---multiply by -6 and add to the 3rd row 0 0 -5 -10 1 0 -3 -4 0 1 2 3 0 0 1 2 <---divided by -5 now back solve

  17. liliy
    • 3 years ago
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    woohooo @phi SO I GOT IT RIGHT???

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