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Kai_
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Solution set?

AcidRa1n
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Well cant X be alot of things?

AcidRa1n
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X could equal 1

AcidRa1n
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15=4 4 times 2 equals 8.. Which is less then 4

AcidRa1n
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is there a way to do this?

AcidRa1n
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your teacher tought you?

Kai_
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Um, first we're told to distribute ( 2) , then I subtracted 10 from both sides

AcidRa1n
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2x+10<4

AcidRa1n
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2x<6

AcidRa1n
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dw:1338859875362:dw

AcidRa1n
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dw:1338859910914:dw

AcidRa1n
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when you divide with a  you switch the sign

AcidRa1n
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thats your answer I believe.. Its been a while since I done this

AcidRa1n
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\[\left\{ x:x > 3 \right\}\]

Kai_
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thanks, thats why i got, but i was unsure.

AcidRa1n
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medal? :P

AcidRa1n
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thanks