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anonymous
 3 years ago
matrix:
2x+3y+ 7z= 13
3x+2y  5z = 22
5x+7y  3z = 28
anonymous
 3 years ago
matrix: 2x+3y+ 7z= 13 3x+2y  5z = 22 5x+7y  3z = 28

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@phi can you help me?

precal
 3 years ago
Best ResponseYou've already chosen the best response.0multiply 3 to the first equation multiply 2 to the second equation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we have to use matrix

precal
 3 years ago
Best ResponseYou've already chosen the best response.0idea is to get rid of one variable at a time matrix  even better can you put it in the calculator?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hahah. no calculators.. this is linear algebra

precal
 3 years ago
Best ResponseYou've already chosen the best response.0yes, well the idea is still the same except with not using the variables

precal
 3 years ago
Best ResponseYou've already chosen the best response.0sorry it has been a long time since I have done linear algebra. I just remember it was my favorite course during my undergrad days....... :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont understand the matrix . can you brief me, i feel like my numbers are always wrong and then the whole thing is wrong

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if i get a matrix of numbers and when it simplifies: 1 0 3 8 0 0 9 3 0 0 8 9

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0these are arbitrarty numbers but if i get two rows that have 0 0 does that mean its bad?

precal
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1338861963247:dw this is your goal in the end

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right, but if you have any rows that are all zeros that means what?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0k, like:: 2 4 6 8 3 6 7 10

precal
 3 years ago
Best ResponseYou've already chosen the best response.0this one has a solution x=1, y=2, z=3

precal
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1338862146454:dw you goal is to create that solution form (sorry I can't even remember its official name, may I be forgiven by the math gods) I would multipy the first row by (1/2) that would force that first term to turn into a 1 but don't forget to change all the other numbers in that row

precal
 3 years ago
Best ResponseYou've already chosen the best response.0I think that is called row multiplication

precal
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wyzant.com/Help/Math/Precalculus/Systems_Of_Equations/Matrix_Method.aspx

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0got it, but for the little example i just posted: 2 4 6 8 3 6 7 10, this matrix, i get the bottom row is 0 0 .. and none of the multiple choices look like that, what am i doing wrong?

precal
 3 years ago
Best ResponseYou've already chosen the best response.0not sure, I put it in my calculator and it does have a solution

precal
 3 years ago
Best ResponseYou've already chosen the best response.0sorry reposted your question but label it, must use the matrix (linear algebra) good luck :) sorry
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