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can you expand your question, or write it in another way..

I did not get it..

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6/36 prob. of the same number

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at least one is 3
11/36

that's all I can do, sorry..

@experimentX : I didnot understand what you did. Would you please explain in another way?

So what would be the final answer?

Everyone has posted a different answer. Who should I trust? :(

toss a coin ... lol

No, seriously. I'm more confused than ever before. :(

If a pair of dice are rolled what is the probability that one die will roll a three?

I think it's \(\frac {11}{36} \)

assuming at-least, if it is strictly one then it is \(\large\frac{10}{36}\)

@FoolForMath Do you intend to reply?

these events are not mutually exclusive. the way you are doing it you are double counting (3,3)

you are describing independence ...the events are independent but they are not mutually exclusive.

@ Zarkon, I think it means at least one of the numbers is 3.
What do u think?