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GOODMAN

  • 2 years ago

Expand: (2s-3t)^5

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  1. saifoo.khan
    • 2 years ago
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    binomial?

  2. GOODMAN
    • 2 years ago
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    Yea.

  3. saifoo.khan
    • 2 years ago
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    dont u know the formula ?

  4. GOODMAN
    • 2 years ago
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    Wasnt given one.

  5. saifoo.khan
    • 2 years ago
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    FAIL.

  6. saifoo.khan
    • 2 years ago
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    http://mathsteaching.files.wordpress.com/2008/05/binomial-expansion-formula.jpg First sentence.

  7. GOODMAN
    • 2 years ago
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    How am I a fail? I wasnt given one or taught one..

  8. saifoo.khan
    • 2 years ago
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    Then how they taught you Binomial expansion?

  9. Eyad
    • 2 years ago
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    32 s^5-240 s^4 t+720 s^3 t^2-1080 s^2 t^3+810 s t^4-243 t^5

  10. GOODMAN
    • 2 years ago
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    No, teacher gave me a page of them to do.

  11. GOODMAN
    • 2 years ago
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    Thank you, Eyad.

  12. Eyad
    • 2 years ago
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    yw :)

  13. saifoo.khan
    • 2 years ago
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    Direct answers! D:

  14. Eyad
    • 2 years ago
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    Under your explanation and your rule :P

  15. GOODMAN
    • 2 years ago
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    You werent helping much, lol. Just telling me that I was a fail. @saifoo.khan Yea, teamwork :)@Eyad

  16. .Sam.
    • 2 years ago
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    (2s-3t)^5 Just expand \[^5C_0(-3t)^0(2s)^5=\] \[^5C_1(-3t)^1(2s)^4=\] \[^5C_2(-3t)^2(2s)^3=\] \[^5C_3(-3t)^3(2s)^2=\] \[^5C_4(-3t)^4(2s)^1=\] \[^5C_5(-3t)^5(2s)^0=\]

  17. GOODMAN
    • 2 years ago
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    And that will be my written answer? Or will I have to expand it further?

  18. .Sam.
    • 2 years ago
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    (p+q)^5 no, you have to use the formula \[^nC_r(q)^r(p)^{n-r}\]

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