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FoolForMath

  • 3 years ago

Fool's problem of the day, A panel of eight umpires (A, B, C, D, E, F, G and H) is selected for officiating all the Cricket matches played in 2002. The countries which they represent (belong to) are P, Q, R, S, T, U and V, not necessarily in the same order. (i) In the panel, B and D only belong to the same country i.e., T, while the others represent different countries. (ii) A belongs to one of the subcontinent countries i.e., Q or U, while G belongs to the other. (iii) The match between R and V is officiated by E and H. (iv) H is does not belong to country P. Note:- The umpires of the same country as the 2 countries that are playing the match cannot officiate in the match. \(Q_1\): If a match is played between countries Q and V, then how many different combinations of umpires for that match are possible? \(Q_2\): If in the above question, it is given that E and H are good friends, and always officiate together in a match, then how many different combinations of umpires are possible for the match between Q and V? Attribution: I faced this question in a selectional test conducted by my coaching institute IMS ( http://www.imsindia.com/ )

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  1. glensstudy
    • 3 years ago
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    Dont know if I'm way off here, but I think its Q1;(9) and Q2;(0)

  2. FoolForMath
    • 3 years ago
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    No.

  3. glensstudy
    • 3 years ago
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    Damn, will try again

  4. nbouscal
    • 3 years ago
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    Is it just me, or is the majority of this information extraneous?

  5. tiaph
    • 3 years ago
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    Yea nbouscal that is what i feel too. Thats why i don't think i got the right answer My answer: Q1. 49 Q2. 25

  6. nbouscal
    • 3 years ago
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    I was getting Q1. 15 and Q2. 7

  7. tiaph
    • 3 years ago
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    May we know the real answer. Thanks!

  8. kropot72
    • 3 years ago
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    The only suitable umpires I could be sure of are B, D, E and H giving the answers: Q1. 6 combinations Q2. 2 combinations

  9. AccessDenied
    • 3 years ago
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    I am getting Q1: 15, Q2: 7 as well. I had to draw an image to visualize how it worked, which is attached. lol

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  10. Glen_McGrath
    • 3 years ago
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    why you call it a FOOL's problem I think it should be Einstein's problem

  11. maheshmeghwal9
    • 3 years ago
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    Ya @Glen_McGrath

  12. siddhantsharan
    • 3 years ago
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    I'm getting Q1 = 24. Q2 = 7. May be wayy off.

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