Fool's problem of the day, A panel of eight umpires (A, B, C, D, E, F, G and H) is selected for officiating all the Cricket matches played in 2002. The countries which they represent (belong to) are P, Q, R, S, T, U and V, not necessarily in the same order. (i) In the panel, B and D only belong to the same country i.e., T, while the others represent different countries. (ii) A belongs to one of the subcontinent countries i.e., Q or U, while G belongs to the other. (iii) The match between R and V is officiated by E and H. (iv) H is does not belong to country P. Note:- The umpires of the same country as the 2 countries that are playing the match cannot officiate in the match. \(Q_1\): If a match is played between countries Q and V, then how many different combinations of umpires for that match are possible? \(Q_2\): If in the above question, it is given that E and H are good friends, and always officiate together in a match, then how many different combinations of umpires are possible for the match between Q and V? Attribution: I faced this question in a selectional test conducted by my coaching institute IMS ( http://www.imsindia.com/ )

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Fool's problem of the day, A panel of eight umpires (A, B, C, D, E, F, G and H) is selected for officiating all the Cricket matches played in 2002. The countries which they represent (belong to) are P, Q, R, S, T, U and V, not necessarily in the same order. (i) In the panel, B and D only belong to the same country i.e., T, while the others represent different countries. (ii) A belongs to one of the subcontinent countries i.e., Q or U, while G belongs to the other. (iii) The match between R and V is officiated by E and H. (iv) H is does not belong to country P. Note:- The umpires of the same country as the 2 countries that are playing the match cannot officiate in the match. \(Q_1\): If a match is played between countries Q and V, then how many different combinations of umpires for that match are possible? \(Q_2\): If in the above question, it is given that E and H are good friends, and always officiate together in a match, then how many different combinations of umpires are possible for the match between Q and V? Attribution: I faced this question in a selectional test conducted by my coaching institute IMS ( http://www.imsindia.com/ )

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Dont know if I'm way off here, but I think its Q1;(9) and Q2;(0)
No.
Damn, will try again

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Is it just me, or is the majority of this information extraneous?
Yea nbouscal that is what i feel too. Thats why i don't think i got the right answer My answer: Q1. 49 Q2. 25
I was getting Q1. 15 and Q2. 7
May we know the real answer. Thanks!
The only suitable umpires I could be sure of are B, D, E and H giving the answers: Q1. 6 combinations Q2. 2 combinations
I am getting Q1: 15, Q2: 7 as well. I had to draw an image to visualize how it worked, which is attached. lol
1 Attachment
why you call it a FOOL's problem I think it should be Einstein's problem
I'm getting Q1 = 24. Q2 = 7. May be wayy off.

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