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FeoNeo33
Group Title
Rational Expressions and Functions:
http://i47.tinypic.com/sbua04.png
 2 years ago
 2 years ago
FeoNeo33 Group Title
Rational Expressions and Functions: http://i47.tinypic.com/sbua04.png
 2 years ago
 2 years ago

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nbouscal Group TitleBest ResponseYou've already chosen the best response.1
I would start by multiplying both sides of the equation by 3x+9 and see what happens :)
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
Thanks, I'll see if that gets me the answer.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
I have a suggestion here. Shall I spit it out?
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
Nah, don't work, it's a fillin answer. @ParthKohli Sure.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Multiply both the numerator and denominator of \(\Large {2 \over x + 3}\).That'll get you two like terms :)
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Multiply both numerator and denominator by 3*
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
okay, bottom is 9, top is 6. Is there another step?
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
I do see the nine and nine, like terms.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
\(\color{Black}{\Rightarrow \Large{1 \over 3x + 9} {3(2) \over 3(x + 3)} }\)
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
I see, but still confusing.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
I don't find anything confusing here. \(\color{Black}{\Rightarrow \Large {x \over y} = {ax \over ay}}\) This is what I am doing here.
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
I know, but this is one of the first units, I'm really, for some reason, having trouble with. Okay, you say, 'Multiply both numerator and denominator by 3*', Okay then what do I do?
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
You'll get two like terms :)
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
First simplify the thing I gave you
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
\[1/3x + 9  6 / x9\] ^^Don't know how to really format it, but the 6 and 9 is there.
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
Or am I missing something
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
\(\color{Black}{\Rightarrow 3(x + 3) = 3x + 9 }\)
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
okay look, we both are going in circles, but probably my fault, but I see the like terms, but what do I do now? :L lol...
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
just operate on the numerators.
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
Nope, couldn't get anything. Okay, I don't want to waste anymore of your precious time, so I'ma ask for a straight up answer? This pellet is just hard for me, point blank.
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
or tell me next steps, I don't mind learning it.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Wolfram if you want the straight answer.
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
lol i just want to learn the steps, but I don't want to waste ur time tutoring me.
 2 years ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
\(\color{Black}{\Rightarrow \Large {1 \over 3x+ 9} {6 \over 3x + 9} = 2 }\) \(\color{Black}{\Rightarrow \Large {5 \over 3x + 9} = 2 }\) Multiply both sides by 3x + 9 \(\color{Black}{\Rightarrow5 = 2(3x+ 9) }\) \(\color{Black}{\Rightarrow 5 = 6x + 18 }\) \(\color{Black}{\Rightarrow 23 = 6x }\) \(\color{Black}{\Rightarrow x = {23 \over 6} }\)
 2 years ago

FeoNeo33 Group TitleBest ResponseYou've already chosen the best response.0
k i was good up till the part with the Multiply both sides by 3x + 9... but Ima let you go, I promise, Im not here just for the answer. Ima learn this stuff, I don't want to be a leecher my whole life. Thanks, bye.
 2 years ago
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