## FeoNeo33 Group Title Rational Expressions and Functions: http://i47.tinypic.com/sbua04.png 2 years ago 2 years ago

1. nbouscal Group Title

I would start by multiplying both sides of the equation by 3x+9 and see what happens :)

2. FeoNeo33 Group Title

Thanks, I'll see if that gets me the answer.

3. ParthKohli Group Title

I have a suggestion here. Shall I spit it out?

4. FeoNeo33 Group Title

Nah, don't work, it's a fill-in answer. @ParthKohli Sure.

5. ParthKohli Group Title

Multiply both the numerator and denominator of $$\Large {2 \over x + 3}$$.That'll get you two like terms :)

6. ParthKohli Group Title

Multiply both numerator and denominator by 3*

7. FeoNeo33 Group Title

okay, bottom is 9, top is 6. Is there another step?

8. FeoNeo33 Group Title

I do see the nine and nine, like terms.

9. ParthKohli Group Title

$$\color{Black}{\Rightarrow \Large{1 \over 3x + 9}- {3(2) \over 3(x + 3)} }$$

10. FeoNeo33 Group Title

I see, but still confusing.

11. ParthKohli Group Title

I don't find anything confusing here. $$\color{Black}{\Rightarrow \Large {x \over y} = {ax \over ay}}$$ This is what I am doing here.

12. FeoNeo33 Group Title

I know, but this is one of the first units, I'm really, for some reason, having trouble with. Okay, you say, 'Multiply both numerator and denominator by 3*', Okay then what do I do?

13. ParthKohli Group Title

You'll get two like terms :)

14. ParthKohli Group Title

First simplify the thing I gave you

15. FeoNeo33 Group Title

$1/3x + 9 - 6 / x9$ ^^Don't know how to really format it, but the 6 and 9 is there.

16. ParthKohli Group Title

No no

17. FeoNeo33 Group Title

Or am I missing something

18. ParthKohli Group Title

$$\color{Black}{\Rightarrow 3(x + 3) = 3x + 9 }$$

19. FeoNeo33 Group Title

okay look, we both are going in circles, but probably my fault, but I see the like terms, but what do I do now? :L lol...

20. ParthKohli Group Title

just operate on the numerators.

21. FeoNeo33 Group Title

Nope, couldn't get anything. Okay, I don't want to waste anymore of your precious time, so I'ma ask for a straight up answer? This pellet is just hard for me, point blank.

22. FeoNeo33 Group Title

or tell me next steps, I don't mind learning it.

23. ParthKohli Group Title

Wolfram if you want the straight answer.

24. FeoNeo33 Group Title

lol i just want to learn the steps, but I don't want to waste ur time tutoring me.

25. ParthKohli Group Title

$$\color{Black}{\Rightarrow \Large {1 \over 3x+ 9} -{6 \over 3x + 9} = 2 }$$ $$\color{Black}{\Rightarrow \Large {-5 \over 3x + 9} = 2 }$$ Multiply both sides by 3x + 9 $$\color{Black}{\Rightarrow-5 = 2(3x+ 9) }$$ $$\color{Black}{\Rightarrow -5 = 6x + 18 }$$ $$\color{Black}{\Rightarrow -23 = 6x }$$ $$\color{Black}{\Rightarrow x = {-23 \over 6} }$$

26. FeoNeo33 Group Title

k i was good up till the part with the Multiply both sides by 3x + 9... but Ima let you go, I promise, Im not here just for the answer. Ima learn this stuff, I don't want to be a leecher my whole life. Thanks, bye.