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I would start by multiplying both sides of the equation by 3x+9 and see what happens :)

Thanks, I'll see if that gets me the answer.

I have a suggestion here. Shall I spit it out?

Nah, don't work, it's a fill-in answer. @ParthKohli Sure.

Multiply both numerator and denominator by 3*

okay, bottom is 9, top is 6. Is there another step?

I do see the nine and nine, like terms.

\(\color{Black}{\Rightarrow \Large{1 \over 3x + 9}- {3(2) \over 3(x + 3)} }\)

I see, but still confusing.

You'll get two like terms :)

First simplify the thing I gave you

\[1/3x + 9 - 6 / x9\] ^^Don't know how to really format it, but the 6 and 9 is there.

No no

Or am I missing something

\(\color{Black}{\Rightarrow 3(x + 3) = 3x + 9 }\)

just operate on the numerators.

or tell me next steps, I don't mind learning it.

Wolfram if you want the straight answer.

lol i just want to learn the steps, but I don't want to waste ur time tutoring me.