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BarlowGirl

  • 3 years ago

PLEASE HELP!!!!! URGENT!!!! Please show steps for the attached problem . . .

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  1. BarlowGirl
    • 3 years ago
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    Evaluate - |dw:1339003375467:dw|

  2. BarlowGirl
    • 3 years ago
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    I got an answer of 91, but the answer choices for the problem don't include that as an answer.

  3. dpaInc
    • 3 years ago
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    since you only have 5 terms, might as well just add them up... 4^2 + 5^2 + 6^2 + 7^2 + 8^2 + 9^2 = 16 + 25 + 36 + 49 + 64 + 81 = ???

  4. BarlowGirl
    • 3 years ago
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    Wait a second, though - aren't there 6 terms (4,5,6,7,8,9)? Don't you include the the k= number AND the number above sigma?

  5. dpaInc
    • 3 years ago
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    you're add k^2 so starting from k=4 to k= 9, you add 4^2 + 5^2 + ... 9^2

  6. dpaInc
    • 3 years ago
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    you should get 271 as the sum of those squares

  7. BarlowGirl
    • 3 years ago
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    Here's the equation for a quadratic series, in case you'd like it: |dw:1339003827921:dw|

  8. BarlowGirl
    • 3 years ago
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    Oh, I see what you're saying. Why doesn't the formula work for this problem, though?

  9. dpaInc
    • 3 years ago
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    that is correct.. but you'll have to subtract k=1 to k=3...|dw:1339003974534:dw|

  10. dpaInc
    • 3 years ago
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    |dw:1339004031135:dw|

  11. BarlowGirl
    • 3 years ago
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    Sorry, I'm a bit confused - what does that mean - "you'll have to subtract k=1 to k=3..." ?

  12. dpaInc
    • 3 years ago
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    so you can use that formula.... but isn't it easier to just write down those 6 terms and add them all up?

  13. BarlowGirl
    • 3 years ago
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    Yes, I do think it's easier, but I wanted to figure out how I could use it with the formula. I don't believe my teacher taught us to subtract the k values - that's why I'm confused.

  14. dpaInc
    • 3 years ago
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    |dw:1339004126864:dw|

  15. BarlowGirl
    • 3 years ago
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    Oh, okay. Thank you very much for your explanation! You've been most helpful! =)

  16. dpaInc
    • 3 years ago
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    yw....:)

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