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anonymous
 4 years ago
PLEASE HELP!!!!! URGENT!!!!!
(problem attached) Please explain how to solve it.
Thank you SO much! =)
anonymous
 4 years ago
PLEASE HELP!!!!! URGENT!!!!! (problem attached) Please explain how to solve it. Thank you SO much! =)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0BTW  the answer is NOT (F)  22 lb. I tried that, and it was incorrect.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you have the equation that models this problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the model for this problem is \(\large y=15(1.09)^t \) , where t is the time in years.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh, I see. So, when I plug 7 into the model, it gives me an approx. answer of: 27 lb. Is this correct?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2If dpalnac is correct about the formula, which I think he is, then the "first year" would be represented mathematically as year 0 (plug in t=0 to get y=15) that means year 7 would be represented as t=6 in your function...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh, I see. Okay. That's what I thought. So then, if it was t=6, then it would be 25 pounds of honey.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2seems that way, but the wording leaves me unable to say that we have interpreted the problem correctly for certain. I get 25 as well though...

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2I can only hope I am reading the problem right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sure, I understand. Thank you very much for trying! :)

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2just following the logic stepbystep\[\text{year1}\implies15\]\[\text{year2}\implies15(1.09)\]\[\text{year3}\implies15(1.09)^2\]so it should be\[\text{year7}\implies15(1.09)^6\]so I think we got it :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Perfect, thank you so much! :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i agree... the wording is .... bleah!
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