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BarlowGirl

PLEASE HELP!!!!! URGENT!!!!! (problem attached) Please explain how to solve it. Thank you SO much! =)

  • one year ago
  • one year ago

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  1. BarlowGirl
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    • one year ago
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  2. BarlowGirl
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    BTW - the answer is NOT (F) - 22 lb. I tried that, and it was incorrect.

    • one year ago
  3. dpaInc
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    do you have the equation that models this problem?

    • one year ago
  4. dpaInc
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    the model for this problem is \(\large y=15(1.09)^t \) , where t is the time in years.

    • one year ago
  5. BarlowGirl
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    Oh, I see. So, when I plug 7 into the model, it gives me an approx. answer of: 27 lb. Is this correct?

    • one year ago
  6. BarlowGirl
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    Is this correct?

    • one year ago
  7. TuringTest
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    If dpalnac is correct about the formula, which I think he is, then the "first year" would be represented mathematically as year 0 (plug in t=0 to get y=15) that means year 7 would be represented as t=6 in your function...

    • one year ago
  8. BarlowGirl
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    Oh, I see. Okay. That's what I thought. So then, if it was t=6, then it would be 25 pounds of honey.

    • one year ago
  9. TuringTest
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    seems that way, but the wording leaves me unable to say that we have interpreted the problem correctly for certain. I get 25 as well though...

    • one year ago
  10. TuringTest
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    I can only hope I am reading the problem right

    • one year ago
  11. BarlowGirl
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    Sure, I understand. Thank you very much for trying! :)

    • one year ago
  12. TuringTest
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    just following the logic step-by-step\[\text{year1}\implies15\]\[\text{year2}\implies15(1.09)\]\[\text{year3}\implies15(1.09)^2\]so it should be\[\text{year7}\implies15(1.09)^6\]so I think we got it :)

    • one year ago
  13. BarlowGirl
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    Perfect, thank you so much! :)

    • one year ago
  14. TuringTest
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    welcome!

    • one year ago
  15. dpaInc
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    i agree... the wording is .... bleah!

    • one year ago
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