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BarlowGirl

  • 3 years ago

PLEASE HELP!!!!! URGENT!!!!! (problem attached) Please explain how to solve it. Thank you SO much! =)

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  1. BarlowGirl
    • 3 years ago
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  2. BarlowGirl
    • 3 years ago
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    BTW - the answer is NOT (F) - 22 lb. I tried that, and it was incorrect.

  3. dpaInc
    • 3 years ago
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    do you have the equation that models this problem?

  4. dpaInc
    • 3 years ago
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    the model for this problem is \(\large y=15(1.09)^t \) , where t is the time in years.

  5. BarlowGirl
    • 3 years ago
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    Oh, I see. So, when I plug 7 into the model, it gives me an approx. answer of: 27 lb. Is this correct?

  6. BarlowGirl
    • 3 years ago
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    Is this correct?

  7. TuringTest
    • 3 years ago
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    If dpalnac is correct about the formula, which I think he is, then the "first year" would be represented mathematically as year 0 (plug in t=0 to get y=15) that means year 7 would be represented as t=6 in your function...

  8. BarlowGirl
    • 3 years ago
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    Oh, I see. Okay. That's what I thought. So then, if it was t=6, then it would be 25 pounds of honey.

  9. TuringTest
    • 3 years ago
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    seems that way, but the wording leaves me unable to say that we have interpreted the problem correctly for certain. I get 25 as well though...

  10. TuringTest
    • 3 years ago
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    I can only hope I am reading the problem right

  11. BarlowGirl
    • 3 years ago
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    Sure, I understand. Thank you very much for trying! :)

  12. TuringTest
    • 3 years ago
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    just following the logic step-by-step\[\text{year1}\implies15\]\[\text{year2}\implies15(1.09)\]\[\text{year3}\implies15(1.09)^2\]so it should be\[\text{year7}\implies15(1.09)^6\]so I think we got it :)

  13. BarlowGirl
    • 3 years ago
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    Perfect, thank you so much! :)

  14. TuringTest
    • 3 years ago
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    welcome!

  15. dpaInc
    • 3 years ago
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    i agree... the wording is .... bleah!

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