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musicalrose

( (1/7)x^2 - (2/5)) * ( (1/2)x + (1/2) )

  • one year ago
  • one year ago

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  1. apoorvk
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    multiply each term of the anyone binomial into the other. Like this: (a+b)(c+d) = a(c+d) + b(c+d)

    • one year ago
  2. musicalrose
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    so..[ (1/7)x^2 * ((1/2)x^2) + (1/2)) ] + [ ((2/5) * ((1/2)x^2) + (1/2)) ] ?

    • one year ago
  3. math456
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    yup thts right..

    • one year ago
  4. apoorvk
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    good except that the (2/5) has a 'minus' sign with it.

    • one year ago
  5. math456
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    \[\left(\begin{matrix}1 \\ 14\end{matrix}\right)x ^{3}+\left(\begin{matrix}1 \\ 14\end{matrix}\right)x ^{2}-\left(\begin{matrix}2 \\ 10\end{matrix}\right)x-\left(\begin{matrix}2 \\ 10\end{matrix}\right)\]

    • one year ago
  6. apoorvk
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    @math456 oop - that notation is actually used for 'combination' or 'C' :P. Other wise it's good.

    • one year ago
  7. musicalrose
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    crap im so lost.

    • one year ago
  8. math456
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    ohh yea i know i couldnt find the division sign thts y i use this..

    • one year ago
  9. apoorvk
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    forget that comment, @musicalrose , you're almost there, just keep in mind that it's a "-2/5" over there, so you include the 'minus' sign as well while multiplying.

    • one year ago
  10. math456
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    @musicalrose i will make it clear.. u use the same concept..

    • one year ago
  11. math456
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    [ (1/7)x^2 *((1/2)x+(1/2) ] - (2/5*((1/2)x^2) + (1/2)) ] ?

    • one year ago
  12. musicalrose
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    yes itd be written like that

    • one year ago
  13. musicalrose
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    .07x^3 + 1/2 for the first part?

    • one year ago
  14. math456
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    (1/14)x3+(1/14)x2−(2/10)x−(2/10) <-- like this

    • one year ago
  15. musicalrose
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    oooh because you made like denominators?

    • one year ago
  16. math456
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    yup... u'll get 0.07 for 1/14

    • one year ago
  17. musicalrose
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    so shouldnt the 1/14x2 actually be 7/14 since it was 1/2x2? or am I not getting it lol

    • one year ago
  18. math456
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    |dw:1339011637725:dw|

    • one year ago
  19. musicalrose
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    I think I get it now..

    • one year ago
  20. math456
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    kool..

    • one year ago
  21. musicalrose
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    thank you tons for spending so much time helping me :)

    • one year ago
  22. math456
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    no problem..!

    • one year ago
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