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Find the following values to the equation of the ellipse (x+5)^2/25 +(y-7)^2/144 = 1. a. Center b. Vertices c. Length of minor axis d. Length of the major axis e. Foci

Mathematics
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here is all you need to answer this question: \[\large \frac {(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 \] where (h,k) is the center vertices for this ellipse: (h,k\(\pm \)b) length of the minor axis: 2a length of major axis: 2b foci: (h,k\(\pm \)c where \(\large c^2 =b^2-a^2\)
let's find (h,k) first... h= k= ??
look at your equation and match it up with the one i wrote... what matches with h and k?

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Other answers:

please hurry i have to have this done in 5 minutes or i fail1!
and thank you! :D
idk what?
\(\large \frac {(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\) \(\large \frac {(x+5)^2}{5^2}+\frac{(y-7)^2}{12^2}=1\)
oh ok
so what are the lengths without vvariables? o.O
for the minor axis, its 2a for the major axis, its 2b you need to tell me what a and b are....
3 minutes!!!!!
but what about the ellipse that is nothing but variables?
a is 5 b is 12
and am i allowed to have variable in the legths?
the equation tells you everything you need to know..... you can identify all these quantities i'm asking for just by looking at your equation...
i already gave you a and b...
so 2a is 10?
yes.
and 2b is 24?>
yes
and the foci and eellipse?
what is c?
use the relation i showed u.... in the first post...
you already know what a and b are.. you can find c...
hmmm i really do not know this plus i am slightly brain dead btw r u a guy or girl
dont i just have get the square roote of c^2 and since c^2=119 than the answer would be 10.9? right?
cookies....why does it matter?
just wanna know
why?
dpanlc?
u there?
idk so i dnt get it wrong
reaally/?
well i'm a girl....soooooooo
yess i dnt wanna be rude kewl glad to have a gal pal

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