Find the following values to the equation of the ellipse (x+5)^2/25 +(y-7)^2/144 = 1.
a. Center
b. Vertices
c. Length of minor axis
d. Length of the major axis
e. Foci

- anonymous

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- anonymous

here is all you need to answer this question:
\[\large \frac {(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 \]
where (h,k) is the center
vertices for this ellipse: (h,k\(\pm \)b)
length of the minor axis: 2a
length of major axis: 2b
foci: (h,k\(\pm \)c
where \(\large c^2 =b^2-a^2\)

- anonymous

let's find (h,k) first...
h=
k=
??

- anonymous

look at your equation and match it up with the one i wrote... what matches with h and k?

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## More answers

- anonymous

please hurry i have to have this done in 5 minutes or i fail1!

- anonymous

and thank you! :D

- anonymous

idk what?

- anonymous

\(\large \frac {(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\)
\(\large \frac {(x+5)^2}{5^2}+\frac{(y-7)^2}{12^2}=1\)

- anonymous

oh ok

- anonymous

so what are the lengths without vvariables? o.O

- anonymous

for the minor axis, its 2a
for the major axis, its 2b
you need to tell me what a and b are....

- anonymous

3 minutes!!!!!

- anonymous

but what about the ellipse that is nothing but variables?

- anonymous

a is 5
b is 12

- anonymous

and am i allowed to have variable in the legths?

- anonymous

the equation tells you everything you need to know..... you can identify all these quantities i'm asking for just by looking at your equation...

- anonymous

i already gave you a and b...

- anonymous

so 2a is 10?

- anonymous

yes.

- anonymous

and 2b is 24?>

- anonymous

yes

- anonymous

and the foci and eellipse?

- anonymous

what is c?

- anonymous

use the relation i showed u.... in the first post...

- anonymous

you already know what a and b are.. you can find c...

- anonymous

hmmm i really do not know this plus i am slightly brain dead btw r u a guy or girl

- anonymous

dont i just have get the square roote of c^2 and since c^2=119 than the answer would be 10.9? right?

- anonymous

cookies....why does it matter?

- anonymous

just wanna know

- anonymous

why?

- anonymous

dpanlc?

- anonymous

u there?

- anonymous

idk so i dnt get it wrong

- anonymous

reaally/?

- anonymous

well i'm a girl....soooooooo

- anonymous

yess i dnt wanna be rude
kewl glad to have a gal pal

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