## GOODMAN Two cards are drawn from a standard deck of 52 cards without replacement. What is the probability that both cards are greater than 2 and less than 9? one year ago one year ago

1. ParthKohli

2. GOODMAN

Thanks little bro, lol. I am studying and forgot this all.

3. ParthKohli

What would be the probability of getting a card between 2 and 9 in the first pick?

4. GOODMAN

2/52 and 9/52

5. ParthKohli

No...it's saying that it's greater than 2 and less than 9. 3,4,5,6,7,8 are the numbers that qualify for me :)

6. GOODMAN

So we have to get the ones in between?

7. ParthKohli

Yes.. exactly

8. ParthKohli

Since there are 3,4,5,6,7,8 in four suits, the probability would be: $$\color{Black}{\Rightarrow \Large {4 \times 6 \over 52} }$$ For the first pick.

9. ParthKohli

Simplifying further: $$\color{Black}{\Rightarrow \Large {24 \over 52} = {12 \over 26} = {6 \over 13} }$$

10. ParthKohli

Now we've picked the first. We have 1 card LESS in the deck because we haven't replaced the cards.

11. ParthKohli

So this time the denominator of the probability would become 51. The numerator will also get one less because we have assumed that we have picked one card which is 3,4,5,6,7 or 8.

12. ParthKohli

There are 23 cards left that we want. 51 total cards left. $$\color{Black}{\Rightarrow \Large {23 \over 51} }$$

13. GOODMAN

Okay...so since we had not replaced, we have to subtract 1?

14. ParthKohli

Now if we want two things to happen at the same time, we shall multiply the probabilities. $$\color{Black}{\Rightarrow \Large {13 \over 26} \times {23 \over 51}}$$

15. ParthKohli

We have to subtract 1 from both numerator and denominator.

16. GOODMAN

Thats it?

17. ParthKohli

Nope

18. GOODMAN

Wait. so after we multiply, we have to simplify further too?

19. ParthKohli

Oops.. I meant this: $$\color{Black}{\Rightarrow \Large {6 \over 13} \times {23 \over 51}}$$

20. ParthKohli

Multiply the fractions. The fractions are in their simplest forms so when we'll multiply it'd be in the simplest form.

21. GOODMAN

Yes, i did that. Okay, so 46/221 is final answer?

22. ParthKohli

How did you get that?

23. ParthKohli

Oh yes

24. ParthKohli

$$\color{Black}{\Rightarrow \Large {2 \over 13} \times {23 \over 17} }$$

25. ParthKohli

Correct! :D

26. GOODMAN

Okay, thats awesome!! Thanks soo much Parth!! Probability is my weak spot :/

27. ParthKohli

Haha probability is easy...getting the hang of what it involves is important

28. GOODMAN

Yea, see, im reviewing this since last semester, lol.

29. ParthKohli

And I've helped someone on this site after a long time. we usually just answer questions ://

30. GOODMAN

Thanks, I actually learned :D