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BarlowGirl
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PLEASE HELP!!!!! URGENT!!!
If I have the compound: S2O2, what is the molar mass? Also, would I need to do anything with the charges, or should I just take 2 moles of S and 2 moles of O and add them together, to get the molar mass?
Thanks! =)
 2 years ago
 2 years ago
BarlowGirl Group Title
PLEASE HELP!!!!! URGENT!!! If I have the compound: S2O2, what is the molar mass? Also, would I need to do anything with the charges, or should I just take 2 moles of S and 2 moles of O and add them together, to get the molar mass? Thanks! =)
 2 years ago
 2 years ago

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UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
the mass of a mole of \(S_2O_2\) is the sum of the molar masses of its parts
 2 years ago

BarlowGirl Group TitleBest ResponseYou've already chosen the best response.0
Okay  so, unless elements in a molecule have ionic charges showing, I should just add the masses of the elements together, like normal?
 2 years ago

BarlowGirl Group TitleBest ResponseYou've already chosen the best response.0
Like what if I have S2Cl  the charges of Cl are not balanced with the charges of the 2S. Do I need to account for the charge difference, in some way, when I go to find the mass?
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
the charge difference will only be due to electrons each electron one \(\frac1{1836}th\) of the weight of a hydrogen nucleus even if the charge difference is ±10 this will not going to effet the mass or molar mass significantly
 2 years ago

BarlowGirl Group TitleBest ResponseYou've already chosen the best response.0
Okay. I do remember my Chem. book saying that.
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
you could add \(0.0005446 \text { amu}\) for any negative charge for each extra electron , and take one off if you had a positive ion , but there wouldn't be much point
 2 years ago

BarlowGirl Group TitleBest ResponseYou've already chosen the best response.0
Oh, okay  I see, now. Thank you very much  you've been great! =)
 2 years ago
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