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mahmit2012
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Q9:suppose that 0<x1<x2<...<xn<pi/2
then show that :
tanx1<(sinx1+sinx2+...+sinxn)/(cosx1+cosx2+...+cosxn)<tanxn
 2 years ago
 2 years ago
mahmit2012 Group Title
Q9:suppose that 0<x1<x2<...<xn<pi/2 then show that : tanx1<(sinx1+sinx2+...+sinxn)/(cosx1+cosx2+...+cosxn)<tanxn
 2 years ago
 2 years ago

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slaaibak Group TitleBest ResponseYou've already chosen the best response.0
not sure how to do this, but I would use a comparison test.. maybe showing that first: tan xn = sin xn/cos xn = nsinxn / ncosxn then showing: [sin x is increasing on x e (0, pi/2) ] (n1)(sin x(n1)) + sin xn < nsinxn [cos x is decreasing on x e (0, pi/2) ] and (n1)(cos x(n1)) + cos xn > ncosxn Then [(n1)(sin x(n1)) + sin xn]/[(n1)(cos x(n1)) + cos xn] < n sin xn/ n cos xn Similar reasoning to show it's > tan x1. but ye, Just a suggestion, it's probably wrong. but ye use if you can..
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.0
what is a (n1)sinx(n1)?and how you use that?
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
it's \[\sin x_{n1}\] n1 times... so \[\sin x_{n1} +\sin x_{n1} +\sin x_{n1} +\sin x_{n1} + ... +\sin x_{n1}\]
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.0
I know !bot I want to solve: tanx1<(sinx1+sinx2+...+sinxn)/(cosx1+cosx2+...+cosxn)<tanxn
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
well, you can't solve that. I'm saying you can use a comparison to prove it... Read my first message thoroughly
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.0
I see your first commend. But choosing those two terms in num and den confusing. However I accept your opinion for sin and cos.
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.0
\[[n.\sin x _{1} \le \sin x _{1}+\sin x _{2}+...\sin x _{n}\le n.\sin x _{n}\\] n.\cos x _{n} \le \cos x _{1}+\cos x _{2}+...\cos x _{n}\le n.\cos x _{1}\]\] as a known a<b<c ,A<B<C => a/C<b/B<c/A so \[\tan x _{1} \le (\sin x _{1}+\sin x _{2}+...\sin x _{n})/(\cos x _{1}+\cos x _{2}+...\cos x _{n}) \le \tan x _{n}\]
 2 years ago
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