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  • 3 years ago

Applications of integration : the line segment x=1-y , 0 <or equal x <or equal 1 is revolved about the y-axis to generate a cone . find its LATERAL surface area.

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  1. RaphaelFilgueiras
    • 3 years ago
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    |dw:1339160052902:dw| S=pi.1.sqrt(2)

  2. Avva
    • 3 years ago
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    I am supposed to use integration to solve ,, for surface area \[s=2\pi \int\limits_{a}^{b} X dL\] but I guess we need to edit this equation to calculate the lateral surface area but I don't know what is it??

  3. Avva
    • 3 years ago
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    The area of the curved (lateral) surface of a cone = πrl I guess I'll remove the 2 from the equation right ? in order to calculate it

  4. RaphaelFilgueiras
    • 3 years ago
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    hum, i dont remeber it

  5. RaphaelFilgueiras
    • 3 years ago
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    i will look in my calc book

  6. Avva
    • 3 years ago
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    I calculated it and figured out it is the same I misunderstood something Thank you the 2 pi in the equation is the revolution of the area it means it will revolve one complete revolution THANKS

  7. RaphaelFilgueiras
    • 3 years ago
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    |dw:1339161279772:dw|

  8. Avva
    • 3 years ago
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    Many Thanks @RaphaelFilgueiras

  9. RaphaelFilgueiras
    • 3 years ago
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    you are welcome

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