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.Sam.Best ResponseYou've already chosen the best response.1
if its solve then (1/2)(32t^2+t+400)=0
 one year ago

.Sam.Best ResponseYou've already chosen the best response.1
\[\begin{array}{l} \frac{1}{2} \left(32 t^2+t+400\right)=0 \\ \text{Divide both sides by }\frac{1}{2} \\ 32 t^2+t+400=0 \\ \text{Use quadratic formula \to solve the equation:} x=\frac{b \pm \sqrt{b^24ac}}{2a} \\\text{Where a=32,b=1,c=400}\\\end{array}\]
 one year ago

.Sam.Best ResponseYou've already chosen the best response.1
\[\huge x=\frac{b \pm \sqrt{b^24ac}}{2a}\] \[\huge x=\frac{1 \pm \sqrt{1^24(32)(400)}}{2(32)}\] \[\huge x=\frac{1 \pm \sqrt{51201}}{64}\] \[\huge x=\frac{1 + \sqrt{51201}}{64}~~~or~~~\huge x=\frac{1  \sqrt{51201}}{64}\]
 one year ago

.Sam.Best ResponseYou've already chosen the best response.1
just replace x as t, its the same
 one year ago
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