anonymous
  • anonymous
Explain how to find the solution to this equation: 64^(x – 3) = 4^(2x)
Mathematics
chestercat
  • chestercat
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maheshmeghwal9
  • maheshmeghwal9
\[64^{x-3}=4^{2x}=>4^{3(x-3)}=4^{2x}\] So \[3(x-3)=2x=>x=9. Ans........\]
maheshmeghwal9
  • maheshmeghwal9
gt it?
anonymous
  • anonymous
Um not 100%. Can you explain please using sentences what you did there...

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maheshmeghwal9
  • maheshmeghwal9
ya ! u have right to know this:) NOTE: - When 2 exponents with same base related by the sign of equality, are anywhere; just do this: - that exponents will be equal.
anonymous
  • anonymous
thanks :)
maheshmeghwal9
  • maheshmeghwal9
yw:) so is it 100%
maheshmeghwal9
  • maheshmeghwal9
i mean did u gt it 200%?
anonymous
  • anonymous
yes I got it! I was solving these fine but idk why I got stumped on that one
maheshmeghwal9
  • maheshmeghwal9
don't worry about maths when u have OS^_^
maheshmeghwal9
  • maheshmeghwal9
OpenStudy*

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