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keeponbleeding

Explain how to find the solution to this equation: 64^(x – 3) = 4^(2x)

  • one year ago
  • one year ago

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  1. maheshmeghwal9
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    \[64^{x-3}=4^{2x}=>4^{3(x-3)}=4^{2x}\] So \[3(x-3)=2x=>x=9. Ans........\]

    • one year ago
  2. maheshmeghwal9
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    gt it?

    • one year ago
  3. keeponbleeding
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    Um not 100%. Can you explain please using sentences what you did there...

    • one year ago
  4. maheshmeghwal9
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    ya ! u have right to know this:) NOTE: - When 2 exponents with same base related by the sign of equality, are anywhere; just do this: - that exponents will be equal.

    • one year ago
  5. keeponbleeding
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    thanks :)

    • one year ago
  6. maheshmeghwal9
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    yw:) so is it 100%

    • one year ago
  7. maheshmeghwal9
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    i mean did u gt it 200%?

    • one year ago
  8. keeponbleeding
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    yes I got it! I was solving these fine but idk why I got stumped on that one

    • one year ago
  9. maheshmeghwal9
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    don't worry about maths when u have OS^_^

    • one year ago
  10. maheshmeghwal9
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    OpenStudy*

    • one year ago
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spraguer (Moderator)
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