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keeponbleeding

  • 3 years ago

Explain how to find the solution to this equation: 64^(x – 3) = 4^(2x)

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  1. maheshmeghwal9
    • 3 years ago
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    \[64^{x-3}=4^{2x}=>4^{3(x-3)}=4^{2x}\] So \[3(x-3)=2x=>x=9. Ans........\]

  2. maheshmeghwal9
    • 3 years ago
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    gt it?

  3. keeponbleeding
    • 3 years ago
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    Um not 100%. Can you explain please using sentences what you did there...

  4. maheshmeghwal9
    • 3 years ago
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    ya ! u have right to know this:) NOTE: - When 2 exponents with same base related by the sign of equality, are anywhere; just do this: - that exponents will be equal.

  5. keeponbleeding
    • 3 years ago
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    thanks :)

  6. maheshmeghwal9
    • 3 years ago
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    yw:) so is it 100%

  7. maheshmeghwal9
    • 3 years ago
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    i mean did u gt it 200%?

  8. keeponbleeding
    • 3 years ago
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    yes I got it! I was solving these fine but idk why I got stumped on that one

  9. maheshmeghwal9
    • 3 years ago
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    don't worry about maths when u have OS^_^

  10. maheshmeghwal9
    • 3 years ago
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    OpenStudy*

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