keeponbleeding
Explain how to find the solution to this equation: 64^(x – 3) = 4^(2x)
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maheshmeghwal9
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\[64^{x-3}=4^{2x}=>4^{3(x-3)}=4^{2x}\] So \[3(x-3)=2x=>x=9. Ans........\]
maheshmeghwal9
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gt it?
keeponbleeding
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Um not 100%. Can you explain please using sentences what you did there...
maheshmeghwal9
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ya ! u have right to know this:)
NOTE: - When 2 exponents with same base related by the sign of equality, are anywhere; just do this: -
that exponents will be equal.
keeponbleeding
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thanks :)
maheshmeghwal9
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yw:)
so is it 100%
maheshmeghwal9
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i mean did u gt it 200%?
keeponbleeding
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yes I got it! I was solving these fine but idk why I got stumped on that one
maheshmeghwal9
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don't worry about maths when u have OS^_^
maheshmeghwal9
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