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this is the last question I can't figure out :/

\[\frac{3}{x}-\frac{3}{x+1}=\frac{3(x+1)-3x}{x(x+1)}=\frac{3}{x(x+1)}.\] Just do the next step:)

i mean: -\[\frac{3}{x(x+1)}-\frac{3}{x+2}\].

now what do u find?

-3(x^2-2)/x(x+1)(x+2)???

ya^_^

phew thank you again!

yw:)