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princeofwetlot

  • 3 years ago

how to solve \[2(2xy + 4y -3)dx + (x+2)^2 dy = 0\] via the Integrating Factor Method (Linear Differential Equations)

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  1. saifoo.khan
    • 3 years ago
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    @dpaInc

  2. princeofwetlot
    • 3 years ago
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    • 3 years ago
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  4. princeofwetlot
    • 3 years ago
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  5. Chlorophyll
    • 3 years ago
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    2( 2xy + 4y −3 )dx + (x+2)² dy = 0 -> dy/dx = - 4y/(x +2) + 6/ (x+2)² 4y/(x +2) + dy/dx = 6/ (x+2)² Let I = e^ 4∫ dx/(x +2) = e^ [ ln (x+2)^4 ] = ( x+2) ^4 => ( x+2) ^4* y = 6 ∫ ( x+2) ^4 dx/ (x+2)² = 6 ∫ (x+2)² dx

  6. Chlorophyll
    • 3 years ago
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    Can you continue from here?

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