Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Can anyone please help me? You need a 20% alcohol solution. On hand, you have a 400 mL of a 15% alcohol mixture. How much pure alcohol will you need to add to obtain the desired solution?
 one year ago
 one year ago
Can anyone please help me? You need a 20% alcohol solution. On hand, you have a 400 mL of a 15% alcohol mixture. How much pure alcohol will you need to add to obtain the desired solution?
 one year ago
 one year ago

This Question is Closed

princeofwetlotBest ResponseYou've already chosen the best response.0
you can set upthe equation as: x mL of 100% alchohol + 400 mL of 15% alcohol = (x + 400) mL of 20% alcohol
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
you have 15% of 400 ml = \(.15\times 400=60\) ml of alcohol at present. if you add say \(x\) ml of alcohol you will have \(60+x\) ml of alcohol and \(400+x\) ml of solution you want \(400+x\) ml to be 20% alcohol, so set \[60+x=.20(400+x)\] and solve for \(x\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
probably easiest to multiply by 10 on both sides to get \[600+10x=2(400+x)\] \[600+10x=800+2x\] \[8x=200\] etc
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
yw hope steps are clear
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.