anonymous
  • anonymous
Can anyone please help me? You need a 20% alcohol solution. On hand, you have a 400 mL of a 15% alcohol mixture. How much pure alcohol will you need to add to obtain the desired solution?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
you can set upthe equation as: x mL of 100% alchohol + 400 mL of 15% alcohol = (x + 400) mL of 20% alcohol
anonymous
  • anonymous
you have 15% of 400 ml = \(.15\times 400=60\) ml of alcohol at present. if you add say \(x\) ml of alcohol you will have \(60+x\) ml of alcohol and \(400+x\) ml of solution you want \(400+x\) ml to be 20% alcohol, so set \[60+x=.20(400+x)\] and solve for \(x\)
anonymous
  • anonymous
probably easiest to multiply by 10 on both sides to get \[600+10x=2(400+x)\] \[600+10x=800+2x\] \[8x=200\] etc

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anonymous
  • anonymous
THANK YOU VERY MUCH!
anonymous
  • anonymous
yw hope steps are clear

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