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ujjwal
Group Title
The number of triangles that can be formed with 10 points as vertices n of them being collinear is 110, then n=
a)3
b)5
c)6
d)4
 2 years ago
 2 years ago
ujjwal Group Title
The number of triangles that can be formed with 10 points as vertices n of them being collinear is 110, then n= a)3 b)5 c)6 d)4
 2 years ago
 2 years ago

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nbouscal Group TitleBest ResponseYou've already chosen the best response.0
Well, we can start with the case of n=0 to give us some intuition, since n=0 will be the maximum number of triangles that can be formed. For the special case n=0, the formula for the number of triangles is simply \(\large{10\choose3}=120\). To go from there, think about how many triangles are ruled out when you add collinear points.
 2 years ago

nbouscal Group TitleBest ResponseYou've already chosen the best response.0
@adarsh\ http://openstudy.com/codeofconduct Please read this.
 2 years ago

adarsh\ Group TitleBest ResponseYou've already chosen the best response.0
Any triangle can be formed by choosing 3 points out of the 10. Now this can be done in three ways: 1) Take three non colinear points. 2) Take one colinear points and twq points from the left over 10n points. 3) Take two colinear points and one of the noncolinear points.
 2 years ago
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