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Harry is trying to solve the equation y = 2x^2 − x − 6 using the quadratic formula. He has made an error in one of the steps below. Find the step where Harry went wrong.

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First of all, do you know what the quadratic formula is?

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Other answers:

I wrote this problem out 6 times, still can't see WHERE he went wrong.
What are you corresponding 'a', 'b' and 'c' for this quadratic when you compare it with the standard equation of a quadratic "ax^2 + bx +c=0"?
A = 2. B = -1. C = -6.
\[1 \pm \sqrt{-1^{2}} - 4*2*-6\]
-12 * -4 = 48. 1*1 = 1. \[1 \pm \sqrt{1-48 } \div 2\]
So it would be
Step 3?
STEP 2!!!
He + instead of -.
Should be : \[x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4 \times 3 \times (-6) }{} }{2\times 2 }\]
No, it'd be -6.
-4 * 2 * -6.
actually the second step itself ha the error. (-1)^2 = 1 and yes that would be -4*2*-6 --> typo my bad.
So, it's step 2, right?
I have one more question.
And please ask questions in the correct subject forum :)
Sure, just post it as a new one!
Oh wow, I didn't realize I was in biology

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