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First of all, do you know what the quadratic formula is?

Yes.

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I wrote this problem out 6 times, still can't see WHERE he went wrong.

A = 2. B = -1. C = -6.

\[1 \pm \sqrt{-1^{2}} - 4*2*-6\]

-12 * -4 = 48.
1*1 = 1. \[1 \pm \sqrt{1-48 } \div 2\]

So it would be

Step 3?

STEP 2!!!

He + instead of -.

Should be :
\[x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4 \times 3 \times (-6) }{} }{2\times 2 }\]

No, it'd be -6.

-4 * 2 * -6.

*has

So, it's step 2, right?

Yup!

I have one more question.

And please ask questions in the correct subject forum :)

Sure, just post it as a new one!

Oh wow, I didn't realize I was in biology

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