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careless850

  • 3 years ago

Harry is trying to solve the equation y = 2x^2 − x − 6 using the quadratic formula. He has made an error in one of the steps below. Find the step where Harry went wrong.

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  1. careless850
    • 3 years ago
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  2. apoorvk
    • 3 years ago
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    First of all, do you know what the quadratic formula is?

  3. careless850
    • 3 years ago
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    Yes.

  4. careless850
    • 3 years ago
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    I wrote this problem out 6 times, still can't see WHERE he went wrong.

  5. apoorvk
    • 3 years ago
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    What are you corresponding 'a', 'b' and 'c' for this quadratic when you compare it with the standard equation of a quadratic "ax^2 + bx +c=0"?

  6. careless850
    • 3 years ago
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    A = 2. B = -1. C = -6.

  7. careless850
    • 3 years ago
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    \[1 \pm \sqrt{-1^{2}} - 4*2*-6\]

  8. careless850
    • 3 years ago
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    -12 * -4 = 48. 1*1 = 1. \[1 \pm \sqrt{1-48 } \div 2\]

  9. careless850
    • 3 years ago
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    So it would be

  10. careless850
    • 3 years ago
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    Step 3?

  11. careless850
    • 3 years ago
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    STEP 2!!!

  12. careless850
    • 3 years ago
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    He + instead of -.

  13. apoorvk
    • 3 years ago
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    Should be : \[x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4 \times 3 \times (-6) }{} }{2\times 2 }\]

  14. careless850
    • 3 years ago
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    No, it'd be -6.

  15. careless850
    • 3 years ago
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    -4 * 2 * -6.

  16. apoorvk
    • 3 years ago
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    actually the second step itself ha the error. (-1)^2 = 1 and yes that would be -4*2*-6 --> typo my bad.

  17. apoorvk
    • 3 years ago
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    *has

  18. careless850
    • 3 years ago
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    So, it's step 2, right?

  19. apoorvk
    • 3 years ago
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    Yup!

  20. careless850
    • 3 years ago
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    I have one more question.

  21. apoorvk
    • 3 years ago
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    And please ask questions in the correct subject forum :)

  22. apoorvk
    • 3 years ago
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    Sure, just post it as a new one!

  23. careless850
    • 3 years ago
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    Oh wow, I didn't realize I was in biology

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