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xRAWRRx3 Group Title

In the diagram below of circle C, QR is a diameter, and Q(1, 8) and C(3.5 , 2) are points on a coordinate plane. Find and state the coordinates of point R.

  • 2 years ago
  • 2 years ago

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  1. xRAWRRx3 Group Title
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    |dw:1339302689432:dw|

    • 2 years ago
  2. Calcmathlete Group Title
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    Use the midpoint formula, but work back wards. (3.5, 2) = (x_1 + x_2/2, y_1 + y_2/2) (7, 4) = (1 + x_2, 8 + y_2) (6, -4) = (x_2, y_2) Therefore, (6, -4)

    • 2 years ago
  3. aceace Group Title
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    (x-3.5)^2 + (y-2)^2 = 6.5^2

    • 2 years ago
  4. xRAWRRx3 Group Title
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    wait, I'm still confused about how to get it...

    • 2 years ago
  5. Calcmathlete Group Title
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    What are you confused on?

    • 2 years ago
  6. aceace Group Title
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    (x- the x co ordinate of c)^2 + (y- the y co ordinate of C) ^2 = the radius squared

    • 2 years ago
  7. Calcmathlete Group Title
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    Point C is the midpoint and therefore you can work backwards using the midpoint formula.

    • 2 years ago
  8. Calcmathlete Group Title
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    @aceace I think you misread the question...

    • 2 years ago
  9. xRAWRRx3 Group Title
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    how do I work backwords though?

    • 2 years ago
  10. aceace Group Title
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    soory if i mis read the question

    • 2 years ago
  11. Calcmathlete Group Title
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    3.5 = (1 + x)/2 7 = 1 + x x = 6 The x coordinate of R is 6. Then work with y. 2 = (8 + y)/2 4 = 8 + y y = -4 Therefore, the y-coordinate of R is -4. R(6, -4)

    • 2 years ago
  12. Calcmathlete Group Title
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    Just focus on one of the values. FOr instance, what I did up there is start with x and then y.

    • 2 years ago
  13. Calcmathlete Group Title
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    Do you get it?\[M(x, y) = ((x_{1} + x_{2})/2, (y_{1} + y_{2})/2)\]

    • 2 years ago
  14. xRAWRRx3 Group Title
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    OHHH. Oh I'm sorry, I was really confused from when you meant backwards but I get it now LOL thank you SO much x)

    • 2 years ago
  15. Calcmathlete Group Title
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    lol. Alright. You're welcome :)

    • 2 years ago
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