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mathsux4real
Please help :0 Find the term containing x^42 of (x^3-3)^16
well first we need \(\frac{42}{3}=14\) to know which term we want
so it is either the 14th term or the second term depending on how you are counting. makes no difference. the term looks like \[\dbinom{16}{2}(x^3)^{14}(-3)^2\]
\[\dbinom{16}{2}=\frac{16\times 15}{2}=8\times 15=120\] and \((-3)^2=9\) multiply to get your answer
wow my drawing really sucked.... oh well!!
Thanks so much satellite73!