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anonymous
 4 years ago
Write an explicit formula for the sequence determined by the recursion formula \[t n = 0.5t _{n1}+n\]
t1=40, t2=22, t3=13, t4 = 8.5, t5=6.25
Please explain how to get to the answer rather than just the answer. Thanks :)
anonymous
 4 years ago
Write an explicit formula for the sequence determined by the recursion formula \[t n = 0.5t _{n1}+n\] t1=40, t2=22, t3=13, t4 = 8.5, t5=6.25 Please explain how to get to the answer rather than just the answer. Thanks :)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1339363260817:dw

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0I used this site to help me understand how to solve this: http://hcmop.wordpress.com/2012/04/20/usingcharacteristicequationtosolvegenerallinearrecurrencerelations/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1339363321532:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your answers are not correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah I just realized that

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0yes  the equation I ended up with agrees with the values found by mahmit2012

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0I can let you know what equation I found if you want  or do you want to try it yourself first?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know the answer, it's tn= ((n+1)(n+2))/2 but I don't know how to get to it

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0I haven't done problems like this before but found that document and followed it to get the answer

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0I actually got:\[t_n=80(\frac{1}{2})^n+2(n1)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah but the textbook gave me the answer I posted. And that website uses very complex explanations :$

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0your formula does not produce the right answers

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0take n=1  it produces the value 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah I just checked, you're right it gave me the wrong answer.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0if you use the formula I derived then it matches all the values (listed by mahmit2012)

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0I can try and explain the steps I took to derive this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, thanks that would be good

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1339364532207:dw

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0ok  first it said arrange the recurrence relation in the form:\[At_n+Bt_{n1}+Ct_{n2}+...=f(n)\]so I arranged your relation as:\[t_n0.5t_{n1}=n\tag{a}\]it then said the general solution when f(n) is zero is \(t_n=A(0.5)^n\). It then said that to take account of f(n) we need to add in a solution of the form \(Bn+C\). So we substitute this into (a) to get:\[Bn+c0.5(B(n1)+C)=n\]which leads to:\[0.5Bn+0.5(B+C)=n\]and if we equate coefficients of LHS and RHS we get:\[B=2\]\[B+C=0\implies C=B=2\]so the second part of the equation is of the form:\[2n2\]we add this to the first part to get the answer:\[t_n=A(0.5)^n+2n2\]then use the fact that \(t_1=40\) to find A.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1339364595544:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1339364644950:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1339364681732:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1339364741953:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1339364774607:dw

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0hope it all makes sense?
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