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ajaykharabe

  • 3 years ago

log

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  1. GOODMAN
    • 3 years ago
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    log of what?

  2. apoorvk
    • 3 years ago
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    Log of nothing is nothing -.-

  3. ajaykharabe
    • 3 years ago
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    \[If \log 5 x=y, then 5^{5y}\]

  4. apoorvk
    • 3 years ago
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    you sure that '5' is adjacent to that 'x', and not the base of log?

  5. mathslover
    • 3 years ago
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    5^y * 5^y * 5^y * 5^y * 5^y = 5^{5y} x^5

  6. ajaykharabe
    • 3 years ago
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    5 is base

  7. ajaykharabe
    • 3 years ago
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    I was not able to type it

  8. ajaykharabe
    • 3 years ago
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    @Hero @saifoo.khan @.Sam. @dpaInc @jim_thompson5910 @lgbasallote @Limitless @UnkleRhaukus

  9. Limitless
    • 3 years ago
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    \(\log(0)\) is actually undefined, @apoorvk.

  10. apoorvk
    • 3 years ago
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    sure then: you gotta use this theorem: \[\large a^{log_bc} = c^{log_b a}\] |dw:1339384039980:dw|

  11. apoorvk
    • 3 years ago
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    yeah @Limitless - i was joking up there^ :p

  12. Limitless
    • 3 years ago
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    :P I figured.

  13. ajaykharabe
    • 3 years ago
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    help in new one

  14. mathslover
    • 3 years ago
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    Yuppie i was correct...

  15. ajaykharabe
    • 3 years ago
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    yes I was choosing you as best answer but apoorvk gave steps

  16. apoorvk
    • 3 years ago
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    Create a new thread for a new question @ajaykharabe

  17. ajaykharabe
    • 3 years ago
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    http://openstudy.com/study#/updates/4fd561fee4b04bec7f1698ee

  18. mathslover
    • 3 years ago
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    @ajaykharabe i dont need medal ... apoorvk is one of the best experts here .. no one can beat him ..............................it is nice to see that u got it :) that is why there is openstudy

  19. apoorvk
    • 3 years ago
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    @mathslover - you deserve this medal, you posted the solution first :) And no, am not an expert - far from it!! :)

  20. mathslover
    • 3 years ago
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    apoorvk i know that i answered it first but the one who explained is you ... no problem that u r not an expert but u r playing the role of expert :)

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