Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.0
what makes you think like that?
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
electrons (or positrons) , and hence current is flowing out of the region
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus, didn't get you. a neutral atom which on decay emits electrons/positrons, hence resulting in current. Now how is kirchoff's law violated in your opinion?
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
Kirchhoff's laws apply only to \(\large \text {electrical circuits}\).
 2 years ago

yakeyglee Group TitleBest ResponseYou've already chosen the best response.0
It's not a violation, because the decay itself is a current. Remeber the continuity equation, which is closely tied to the conservation of charge: \[\vec \nabla \cdot \vec J = \frac{\partial \rho}{\partial t}\]
 2 years ago

PaxPolaris Group TitleBest ResponseYou've already chosen the best response.0
I think he means that current flowing into the decaying atom(0) is not the same as current flowing out.. but circuit laws shouldn't apply to the atom
 2 years ago

yakeyglee Group TitleBest ResponseYou've already chosen the best response.0
It's honestly more of a conservation of charge concept. Think about a capacitor. Even though current doesn't flow through, charge is still conserved as it collects on the plates, and thus we don't think twice about it when we apply Kirchoff's Current Law. If we think of each of the plates themselves as junctions, we find that the current flowing in is NOT the current flowing out. It's a similar concept here. It's not that it's a violation, it's rather that Kirchoff's Current Law has no place in microscopic electrodynamics.
 2 years ago

Carl_Pham Group TitleBest ResponseYou've already chosen the best response.0
How can it? Charge is always conserved. In beta decay you emit an electron, and the nucleus acquires another positive charge. That either leaves you with a cation  in which case you have a current of both electrons and positive anions, i.e. a neutral current  or the cation absorbs a nearby electron, which cancels out the charge of the beta particle. It's true when you think about nuclear physics, you tend to ignore the behaviour of any orbital electrons, or indeed any electrons at thermal (and not nuclear) energies. But they're there, and in cases interact to balance the books.
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.