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@apoorvk @satellite73 @A.Avinash_Goutham @ajprincess @AndrewNJ
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
okay, expand the two wholesquares, it's simple enough...
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
the options are 4cos^2(ab/2) 4 sin a/2 cos b/2
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
dw:1339426035616:dw
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
@apoorvk after expanding i got this then next..............
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
great, now.. cosAcosB + sinAsinB = cos(AB) Use this^
 2 years ago

patmyer1 Group TitleBest ResponseYou've already chosen the best response.0
ugh, trig identities are a drag. Even after deriving them myself I simply CANNOT seem to memorize them
 2 years ago

AndrewNJ Group TitleBest ResponseYou've already chosen the best response.1
spread it so we have (cosa)^2+(cosb)^2+2(cosa)(cosb)+(sina)^2+(sinb)^2+2(sina)(sinb) =2+2cos(ab)
 2 years ago

AndrewNJ Group TitleBest ResponseYou've already chosen the best response.1
(cosa)^2+(sina)^2=1 (cosb)^2+(sinb)^2=1 (cosa)(cosb)+(sina)(sinb)=cos(ab)
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
ok @apoorvk so it is not over yet!!@
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.2
Continuing from where @AndrewNJ left, \[2(1+\cos(ab))\] now we know that \[1 + \cos 2a = 2 \cos^2 a\] Now try :D
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
@shivam_bhalla did nt understand!
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.2
= \[2(1+\cos 2\frac{(ab)}{2})\] Now we have a identity, \[1 + \cos 2x = 2 \cos^2 x\] in your case, \[x = \frac{ab}{2}\] Now try
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
i got it thxx @shivam_bhalla
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.2
Your welcome :)
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
@shivam_bhalla plzz help http://openstudy.com/study?signup#/updates/4fd60c0be4b04bec7f170b7d
 2 years ago
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