anonymous
  • anonymous
Is there a simple way to understand test cross of dihybrid plants? involving punnette square?
Biology
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
punnett square I always use this method for my genetic question.
blues
  • blues
Yes - Punnett squares are very useful for this. A test cross is recessive for all traits of interest - so for a dihybrid cross that means, aabb where a is the first gene and b is the second.
anonymous
  • anonymous
thank you! However my teacher loves to give us questions where she provide us with the ratio of offsprings and we have to find the parental genotype. How do I do this kind of questions??

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
even my teacher @Natshane
anonymous
  • anonymous
hehehehe....I'm asking YY to teach me after class tests...
anonymous
  • anonymous
Use punnett square. Let say a couple has one AB type child and one O type child. You draw punnett square and filling in the child's genotype. The middle box is filled by AB and the bottom right is by O-type. Since the child receive each allele from each parent, you can 'trace back' the parental genotype. If the child is AB, one parent will have one A allele and the other will have B allele. If the child is O type, he receive each O allele from each parent. Now you can roughly figure the parent's genotype. |dw:1339531802278:dw| I hope this helps.
anonymous
  • anonymous
Oh! This seems to be so much easier to understand! Thank you @yukitou! I'll try to do it this way for my other questions. But what if the question is given ratio 148 wrinkled, yellow, 24 wrinkled green that kind of question? isn't it harder to find using a punnett square?
anonymous
  • anonymous
you mean dihybrid cross? The punnett square is still very useful. Let say parental genotypes are RR/yy and rr/YY where R is round, r is wrinkled, y is green and Y is yellow. When they cross, F1 genotype is Rr/Yy. |dw:1339599269501:dw| then, you self-cross this F1to get F2 genotype.|dw:1339599523841:dw| Well, you will get 4 different phenotype with 9 different genotype. The phenotype ratio is 9:3:3:1 where by 9 is R-/Y-, 3 is R-/yy, another 3 is for rr/Y- and the 1 is rr/yy. The dash means the allele can be either dominant or recessive because it still won't affect the effect of dominant allele. i hope this helps.
anonymous
  • anonymous
Thank you! I'll try it on my exercise questions now.

Looking for something else?

Not the answer you are looking for? Search for more explanations.