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 2 years ago
How do you determine if linear equations are parallel without graphing like
2x + 2y=4
3x +y=3
 2 years ago
How do you determine if linear equations are parallel without graphing like 2x + 2y=4 3x +y=3

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lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1simplify the equations as much as possible for example 2x + 2y = 4 i can divide all terms by 2 and simplify it to x + y = 2 got that part?

ashleysmith
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah , after you simplify it how do you know if it's parallel or perpendicular

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1you look at the next equation (note that it has to be simplified as much as possible too) our first equation is x + y = 2 if our second equation is also x+y = c <c is a constant (which means it is any number)..the important thing is the x+y if the left sides of BOTH equations look EXACTLY the same then they are parallel got it?

ashleysmith
 2 years ago
Best ResponseYou've already chosen the best response.0Yeah what if the slope is the same ?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1when the slopes are the same then they are parallel

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1to know if it is perpendicular...simplify the equations again...then put it in the form ax + by = c so you can see it better now when the left sides of BOTH equations look the same BUT the only difference is the sign of x, then they are perpendicular

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1would you like an example?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1okay... 2x + 2y = 4 3y = 9  3x the first step is to simplify both equations..i divide the first equation by 2 and get x + y = 2 now i divide the second equation by 3 (since it is common to all terms) y = 3  x now the second step is to put in the form ax + by = c the first equation is already in that form so no worries the second equation would then look like x + y = 3 now let us compare (1) x + y = 2 (2) x + y = 3 what can you say?
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