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Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
\(2bxb=5\) Solve for \(x\)? Leaving \(b\) as a variable?
 2 years ago

rosimary Group TitleBest ResponseYou've already chosen the best response.0
I'm sorry I don't understand
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
Well, solve for \(x\) and leave it in terms of \(b\)?
 2 years ago

thechocoluver445 Group TitleBest ResponseYou've already chosen the best response.1
dw:1339465613099:dw
 2 years ago

thechocoluver445 Group TitleBest ResponseYou've already chosen the best response.1
You basically isolate the term(s) that include the desired variable, take away the other stuff that the variable multiplies with, and divide the other side by it.
 2 years ago

rosimary Group TitleBest ResponseYou've already chosen the best response.0
wouldn't the b = 1b so it would be x=5/2b instead?
 2 years ago

thechocoluver445 Group TitleBest ResponseYou've already chosen the best response.1
no, because the numerator has two different terms on it. you can't do that
 2 years ago

rosimary Group TitleBest ResponseYou've already chosen the best response.0
Thank you so much
 2 years ago

thechocoluver445 Group TitleBest ResponseYou've already chosen the best response.1
dw:1339466008518:dw
 2 years ago

thechocoluver445 Group TitleBest ResponseYou've already chosen the best response.1
no problem (:
 2 years ago
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