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\[2x^2-12x +16=0\]

please explain each step
I am having trouble with it

2(x^2-6x+8)=0
2[(x-4)(x-2)]=0

please do explain why you do each step

Those 2 values are then put into the brackets as you see them.

ok but there is supposed to be two answers

4 is one of them

|dw:1339466532153:dw|

|dw:1339466562615:dw|

|dw:1339466604939:dw|

eh, you might be might be making this more difficult than it actually is

I did what the question asked. Solve quadratic equation by completing the square.

ay. missed that. thx.

You made a small mistake. The -8 should also be multiplied by -2.

Just 2 rather.

Leaving you with\[2(x^2-6x+9-9+8)=2((x-3)^2-1)=2(x-3)^2-2\]

ok george you are right now can you explain each step

Did this make sense?

yes thank you but please view my next question