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countonme123

  • 2 years ago

quadratic equation by completing the square. check both roots . equation below

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  1. countonme123
    • 2 years ago
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    \[x^2-6x=7\]

  2. countonme123
    • 2 years ago
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    please explain each step

  3. NotTim
    • 2 years ago
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    well, first subtract 7 from both sides.

  4. satellite73
    • 2 years ago
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    take half of 6 get 3 write \[(x-3)^2=7+...\] then think "3 squared is 9" write \[(x-3)^2=7+9=16\] take the root, don't forget the \(\pm\) get \[x-3=\pm\sqrt{16}\] \[x-3=\pm4\]

  5. satellite73
    • 2 years ago
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    then solve \[x-3=4\iff x=7\] or \[x-3=-4\iff x=-1\]

  6. satellite73
    • 2 years ago
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    all the steps are there

  7. countonme123
    • 2 years ago
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    wow i think i get it let me try it on paper

  8. countonme123
    • 2 years ago
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    hmm thats not right

  9. countonme123
    • 2 years ago
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    wait my mistake you got half right but there is supposed to be one more answer

  10. NotTim
    • 2 years ago
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    no...satellite gave enough I think. There's 2 values for x in his answer. I dont think there's a third one is a trinomial like this.

  11. countonme123
    • 2 years ago
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    you are right my bad again i didnt see or

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