Here's the question you clicked on:
countonme123
quadratic equation by completing the square. check both roots . equation below
please explain each step
well, first subtract 7 from both sides.
take half of 6 get 3 write \[(x-3)^2=7+...\] then think "3 squared is 9" write \[(x-3)^2=7+9=16\] take the root, don't forget the \(\pm\) get \[x-3=\pm\sqrt{16}\] \[x-3=\pm4\]
then solve \[x-3=4\iff x=7\] or \[x-3=-4\iff x=-1\]
all the steps are there
wow i think i get it let me try it on paper
hmm thats not right
wait my mistake you got half right but there is supposed to be one more answer
no...satellite gave enough I think. There's 2 values for x in his answer. I dont think there's a third one is a trinomial like this.
you are right my bad again i didnt see or