## countonme123 quadratic equation by completing the square. check both roots . equation below one year ago one year ago

1. countonme123

$x^2-6x=7$

2. countonme123

3. NotTim

well, first subtract 7 from both sides.

4. satellite73

take half of 6 get 3 write $(x-3)^2=7+...$ then think "3 squared is 9" write $(x-3)^2=7+9=16$ take the root, don't forget the $$\pm$$ get $x-3=\pm\sqrt{16}$ $x-3=\pm4$

5. satellite73

then solve $x-3=4\iff x=7$ or $x-3=-4\iff x=-1$

6. satellite73

all the steps are there

7. countonme123

wow i think i get it let me try it on paper

8. countonme123

hmm thats not right

9. countonme123

wait my mistake you got half right but there is supposed to be one more answer

10. NotTim

no...satellite gave enough I think. There's 2 values for x in his answer. I dont think there's a third one is a trinomial like this.

11. countonme123

you are right my bad again i didnt see or