Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

quadratic equation by completing the square. check both roots . equation below

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
\[x^2-6x=7\]
please explain each step
well, first subtract 7 from both sides.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

take half of 6 get 3 write \[(x-3)^2=7+...\] then think "3 squared is 9" write \[(x-3)^2=7+9=16\] take the root, don't forget the \(\pm\) get \[x-3=\pm\sqrt{16}\] \[x-3=\pm4\]
then solve \[x-3=4\iff x=7\] or \[x-3=-4\iff x=-1\]
all the steps are there
wow i think i get it let me try it on paper
hmm thats not right
wait my mistake you got half right but there is supposed to be one more answer
no...satellite gave enough I think. There's 2 values for x in his answer. I dont think there's a third one is a trinomial like this.
you are right my bad again i didnt see or

Not the answer you are looking for?

Search for more explanations.

Ask your own question