## anonymous 4 years ago quadratic equation by completing the square. check both roots . equation below

1. anonymous

$x^2-6x=7$

2. anonymous

3. NotTim

well, first subtract 7 from both sides.

4. anonymous

take half of 6 get 3 write $(x-3)^2=7+...$ then think "3 squared is 9" write $(x-3)^2=7+9=16$ take the root, don't forget the $$\pm$$ get $x-3=\pm\sqrt{16}$ $x-3=\pm4$

5. anonymous

then solve $x-3=4\iff x=7$ or $x-3=-4\iff x=-1$

6. anonymous

all the steps are there

7. anonymous

wow i think i get it let me try it on paper

8. anonymous

hmm thats not right

9. anonymous

wait my mistake you got half right but there is supposed to be one more answer

10. NotTim

no...satellite gave enough I think. There's 2 values for x in his answer. I dont think there's a third one is a trinomial like this.

11. anonymous

you are right my bad again i didnt see or