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RaphaelFilgueiras

  • 2 years ago

Suppose an ISP has the addres like 101.101.128/17.He want to create 4 subnets.What are the prefix (a.b.c.d/x) for this four subnets?

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  1. RaphaelFilgueiras
    • 2 years ago
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    @izanagi.wielder

  2. izanagi.wielder
    • 2 years ago
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    wait i will have think

  3. RaphaelFilgueiras
    • 2 years ago
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    i forgot to mention every block mus be the same number of IP address

  4. izanagi.wielder
    • 2 years ago
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    101.101.101.64/28 101.101.101.80/28 101.101.101.96/28 101.101.101.112/28

  5. RaphaelFilgueiras
    • 2 years ago
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    how u get it? izanagi

  6. izanagi.wielder
    • 2 years ago
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    well my bro is a cs learner i asked him

  7. RaphaelFilgueiras
    • 2 years ago
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    lol,ask for him how to get the result please

  8. izanagi.wielder
    • 2 years ago
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    you can contact him later @Ishaan94

  9. RaphaelFilgueiras
    • 2 years ago
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    ok

  10. RaphaelFilgueiras
    • 2 years ago
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    thanks

  11. izanagi.wielder
    • 2 years ago
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    101.101.128.0/19 101.101.160.0/19 101.101.192.0/19 101.101.224.0/19

  12. izanagi.wielder
    • 2 years ago
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    these are other answers my bro says break it into 4 equal pieces

  13. RaphaelFilgueiras
    • 2 years ago
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    i do it like this too,but the ans is equal to first form,and i dont know why we use /28 instead /19

  14. RaphaelFilgueiras
    • 2 years ago
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    to make four subnets i must borrow 2 bits from the host,i think

  15. izanagi.wielder
    • 2 years ago
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    i am not that deep in it you better contact him

  16. RaphaelFilgueiras
    • 2 years ago
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    ok thanks izanagi

  17. izanagi.wielder
    • 2 years ago
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    welcome

  18. SigurdS
    • 2 years ago
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    You need to convert to binary, each is 8 long in binary so 101.101.128.0/17 converts to: 01100101.01100101.10000000.00000000 The 17 means the 17 first bits will be equal to each adress, this equals to: 01100101.01100101.1 (8+8+1) Now you have 0000000.00000000 to make 4 equal subnets with, 15 bits To get 4 different we need to use 2 bits, 00 / 01 / 10 / 11 This will give us the 4 subnets, now with added 2 bits: 01100101.01100101.100 = 101.101.128.0/19 01100101.01100101.101 = 101.101.160.0/19 01100101.01100101.110 = 101.101.192.0/19 01100101.01100101.111 = 101.101.224.0/19 Hope this helps :)

  19. RaphaelFilgueiras
    • 2 years ago
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    @SigurdS i thougth samething but the answ in book is: 101.101.101.64/28 101.101.101.80/28 101.101.101.96/28 101.101.101.112/28

  20. SigurdS
    • 2 years ago
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    I think the book is wrong, ask your professor but those are not the same subnets as the one mentioned in the question, as the extra 101 block will not fall into the 128, (01100101 vs 10000000) Books often do silly mistakes like that! (I am not a 100% expert on subnetting so I might be missing something)

  21. RaphaelFilgueiras
    • 2 years ago
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    thanks

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