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RaphaelFilgueiras Group Title

Suppose an ISP has the addres like 101.101.128/17.He want to create 4 subnets.What are the prefix (a.b.c.d/x) for this four subnets?

  • 2 years ago
  • 2 years ago

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  1. RaphaelFilgueiras Group Title
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    @izanagi.wielder

    • 2 years ago
  2. izanagi.wielder Group Title
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    wait i will have think

    • 2 years ago
  3. RaphaelFilgueiras Group Title
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    i forgot to mention every block mus be the same number of IP address

    • 2 years ago
  4. izanagi.wielder Group Title
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    101.101.101.64/28 101.101.101.80/28 101.101.101.96/28 101.101.101.112/28

    • 2 years ago
  5. RaphaelFilgueiras Group Title
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    how u get it? izanagi

    • 2 years ago
  6. izanagi.wielder Group Title
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    well my bro is a cs learner i asked him

    • 2 years ago
  7. RaphaelFilgueiras Group Title
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    lol,ask for him how to get the result please

    • 2 years ago
  8. izanagi.wielder Group Title
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    you can contact him later @Ishaan94

    • 2 years ago
  9. RaphaelFilgueiras Group Title
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    ok

    • 2 years ago
  10. RaphaelFilgueiras Group Title
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    thanks

    • 2 years ago
  11. izanagi.wielder Group Title
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    101.101.128.0/19 101.101.160.0/19 101.101.192.0/19 101.101.224.0/19

    • 2 years ago
  12. izanagi.wielder Group Title
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    these are other answers my bro says break it into 4 equal pieces

    • 2 years ago
  13. RaphaelFilgueiras Group Title
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    i do it like this too,but the ans is equal to first form,and i dont know why we use /28 instead /19

    • 2 years ago
  14. RaphaelFilgueiras Group Title
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    to make four subnets i must borrow 2 bits from the host,i think

    • 2 years ago
  15. izanagi.wielder Group Title
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    i am not that deep in it you better contact him

    • 2 years ago
  16. RaphaelFilgueiras Group Title
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    ok thanks izanagi

    • 2 years ago
  17. izanagi.wielder Group Title
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    welcome

    • 2 years ago
  18. SigurdS Group Title
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    You need to convert to binary, each is 8 long in binary so 101.101.128.0/17 converts to: 01100101.01100101.10000000.00000000 The 17 means the 17 first bits will be equal to each adress, this equals to: 01100101.01100101.1 (8+8+1) Now you have 0000000.00000000 to make 4 equal subnets with, 15 bits To get 4 different we need to use 2 bits, 00 / 01 / 10 / 11 This will give us the 4 subnets, now with added 2 bits: 01100101.01100101.100 = 101.101.128.0/19 01100101.01100101.101 = 101.101.160.0/19 01100101.01100101.110 = 101.101.192.0/19 01100101.01100101.111 = 101.101.224.0/19 Hope this helps :)

    • 2 years ago
  19. RaphaelFilgueiras Group Title
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    @SigurdS i thougth samething but the answ in book is: 101.101.101.64/28 101.101.101.80/28 101.101.101.96/28 101.101.101.112/28

    • 2 years ago
  20. SigurdS Group Title
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    I think the book is wrong, ask your professor but those are not the same subnets as the one mentioned in the question, as the extra 101 block will not fall into the 128, (01100101 vs 10000000) Books often do silly mistakes like that! (I am not a 100% expert on subnetting so I might be missing something)

    • 2 years ago
  21. RaphaelFilgueiras Group Title
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    thanks

    • 2 years ago
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