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anonymous
 3 years ago
Suppose an ISP has the addres like 101.101.128/17.He want to create 4 subnets.What are the prefix (a.b.c.d/x) for this four subnets?
anonymous
 3 years ago
Suppose an ISP has the addres like 101.101.128/17.He want to create 4 subnets.What are the prefix (a.b.c.d/x) for this four subnets?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait i will have think

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i forgot to mention every block mus be the same number of IP address

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0101.101.101.64/28 101.101.101.80/28 101.101.101.96/28 101.101.101.112/28

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how u get it? izanagi

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well my bro is a cs learner i asked him

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol,ask for him how to get the result please

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you can contact him later @Ishaan94

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0101.101.128.0/19 101.101.160.0/19 101.101.192.0/19 101.101.224.0/19

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0these are other answers my bro says break it into 4 equal pieces

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i do it like this too,but the ans is equal to first form,and i dont know why we use /28 instead /19

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0to make four subnets i must borrow 2 bits from the host,i think

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am not that deep in it you better contact him

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You need to convert to binary, each is 8 long in binary so 101.101.128.0/17 converts to: 01100101.01100101.10000000.00000000 The 17 means the 17 first bits will be equal to each adress, this equals to: 01100101.01100101.1 (8+8+1) Now you have 0000000.00000000 to make 4 equal subnets with, 15 bits To get 4 different we need to use 2 bits, 00 / 01 / 10 / 11 This will give us the 4 subnets, now with added 2 bits: 01100101.01100101.100 = 101.101.128.0/19 01100101.01100101.101 = 101.101.160.0/19 01100101.01100101.110 = 101.101.192.0/19 01100101.01100101.111 = 101.101.224.0/19 Hope this helps :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@SigurdS i thougth samething but the answ in book is: 101.101.101.64/28 101.101.101.80/28 101.101.101.96/28 101.101.101.112/28

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think the book is wrong, ask your professor but those are not the same subnets as the one mentioned in the question, as the extra 101 block will not fall into the 128, (01100101 vs 10000000) Books often do silly mistakes like that! (I am not a 100% expert on subnetting so I might be missing something)
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