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RaphaelFilgueiras
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Suppose an ISP has the addres like 101.101.128/17.He want to create 4 subnets.What are the prefix (a.b.c.d/x) for this four subnets?
 2 years ago
 2 years ago
RaphaelFilgueiras Group Title
Suppose an ISP has the addres like 101.101.128/17.He want to create 4 subnets.What are the prefix (a.b.c.d/x) for this four subnets?
 2 years ago
 2 years ago

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RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
@izanagi.wielder
 2 years ago

izanagi.wielder Group TitleBest ResponseYou've already chosen the best response.0
wait i will have think
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
i forgot to mention every block mus be the same number of IP address
 2 years ago

izanagi.wielder Group TitleBest ResponseYou've already chosen the best response.0
101.101.101.64/28 101.101.101.80/28 101.101.101.96/28 101.101.101.112/28
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
how u get it? izanagi
 2 years ago

izanagi.wielder Group TitleBest ResponseYou've already chosen the best response.0
well my bro is a cs learner i asked him
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
lol,ask for him how to get the result please
 2 years ago

izanagi.wielder Group TitleBest ResponseYou've already chosen the best response.0
you can contact him later @Ishaan94
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
ok
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
thanks
 2 years ago

izanagi.wielder Group TitleBest ResponseYou've already chosen the best response.0
101.101.128.0/19 101.101.160.0/19 101.101.192.0/19 101.101.224.0/19
 2 years ago

izanagi.wielder Group TitleBest ResponseYou've already chosen the best response.0
these are other answers my bro says break it into 4 equal pieces
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
i do it like this too,but the ans is equal to first form,and i dont know why we use /28 instead /19
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
to make four subnets i must borrow 2 bits from the host,i think
 2 years ago

izanagi.wielder Group TitleBest ResponseYou've already chosen the best response.0
i am not that deep in it you better contact him
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
ok thanks izanagi
 2 years ago

izanagi.wielder Group TitleBest ResponseYou've already chosen the best response.0
welcome
 2 years ago

SigurdS Group TitleBest ResponseYou've already chosen the best response.2
You need to convert to binary, each is 8 long in binary so 101.101.128.0/17 converts to: 01100101.01100101.10000000.00000000 The 17 means the 17 first bits will be equal to each adress, this equals to: 01100101.01100101.1 (8+8+1) Now you have 0000000.00000000 to make 4 equal subnets with, 15 bits To get 4 different we need to use 2 bits, 00 / 01 / 10 / 11 This will give us the 4 subnets, now with added 2 bits: 01100101.01100101.100 = 101.101.128.0/19 01100101.01100101.101 = 101.101.160.0/19 01100101.01100101.110 = 101.101.192.0/19 01100101.01100101.111 = 101.101.224.0/19 Hope this helps :)
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
@SigurdS i thougth samething but the answ in book is: 101.101.101.64/28 101.101.101.80/28 101.101.101.96/28 101.101.101.112/28
 2 years ago

SigurdS Group TitleBest ResponseYou've already chosen the best response.2
I think the book is wrong, ask your professor but those are not the same subnets as the one mentioned in the question, as the extra 101 block will not fall into the 128, (01100101 vs 10000000) Books often do silly mistakes like that! (I am not a 100% expert on subnetting so I might be missing something)
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
thanks
 2 years ago
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