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agillogly

  • 3 years ago

write (cos pi/4+ i sin pi/4)^3 in trigonometric form

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  1. anonymous
    • 3 years ago
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    multiply the angle by three

  2. anonymous
    • 3 years ago
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    \[\cos(\frac{3\pi}{4})+i\sin(\frac{3\pi}{4})\]

  3. anonymous
    • 3 years ago
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    you also have to cube the modulus, but since it is one you just get one, so you can ignore that part now if you want to write this in standard form as \(a+bi\) evaluate the functions and see what you get

  4. agillogly
    • 3 years ago
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    thanks.

  5. anonymous
    • 3 years ago
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    \[(\cos(\theta)+i\sin(\theta))^n=\cos(n\theta)+i\sin(n\theta)\] that is what makes this so easy

  6. anonymous
    • 3 years ago
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    yw

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