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Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 2, – 16), and x intercepts at x = 6 and x = 2. (Do not include the negative sign in your answer.)
y = x2 + 4x  ___
 one year ago
 one year ago
Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of (– 2, – 16), and x intercepts at x = 6 and x = 2. (Do not include the negative sign in your answer.) y = x2 + 4x  ___
 one year ago
 one year ago

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campbell_stBest ResponseYou've already chosen the best response.0
if it has intercepts at x = 6 and x = 2 and a vertex at (2, 16) the parabola is concave up. then the equation is y= (x +6)(x 2) expanding gives y = x^2 + 4x  12
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
the missing value is 12
 one year ago
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