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How do you solve something like this: 16!/4!12! (The 4!12! are underneath the 16 though. So it looks like a fraction.)

Mathematics
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You can start expanding it:\[{16! \over {4!12!}} = {{16 \times 15 \times 14 \times 13 \times 12!} \over {4! 12!}}\]Then cross out the 12! and... you can solve the rest ;)
|dw:1339537456038:dw|
\[(16 \times 15 \times 14 \times 13 \times 12!)/((4 \times 3 \times 2 \times 1) \times 12!)\] 1820

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