## anonymous 4 years ago How do you solve something like this: 16!/4!12! (The 4!12! are underneath the 16 though. So it looks like a fraction.)

1. anonymous

You can start expanding it:${16! \over {4!12!}} = {{16 \times 15 \times 14 \times 13 \times 12!} \over {4! 12!}}$Then cross out the 12! and... you can solve the rest ;)

2. anonymous

|dw:1339537456038:dw|

3. anonymous

$(16 \times 15 \times 14 \times 13 \times 12!)/((4 \times 3 \times 2 \times 1) \times 12!)$ 1820