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shahzadjalbani Group Title

what is f(x) ? if f(x-1)=x^2+3x+5

  • 2 years ago
  • 2 years ago

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  1. pratu043 Group Title
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    I'm not sure, but I think its (x + 1)^2 + 3(x - 1) + 5

    • 2 years ago
  2. princeofwetlot Group Title
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    f(x) = f[(x -1) + 1]

    • 2 years ago
  3. princeofwetlot Group Title
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    yup that's right @pratu043 :)

    • 2 years ago
  4. shahzadjalbani Group Title
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    explain @pratu043

    • 2 years ago
  5. princeofwetlot Group Title
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    lol look at what i wrote...f(x-1 + 1) = f(x + 0) = f(x) since f(x-1) = x^2 + 3x + 5 f(x - 1 + 1) = (x+1)^2 + 3(x+1) + 5 got the logic?

    • 2 years ago
  6. shahzadjalbani Group Title
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    1 and 1 will be cancelled then there will f(x) I didn't get.

    • 2 years ago
  7. princeofwetlot Group Title
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    hmmm you get that f(x-1 + 1) = f(x) right?

    • 2 years ago
  8. princeofwetlot Group Title
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    now let a = x-1 f(a) = a^2 + 3a + 5 agree?

    • 2 years ago
  9. shahzadjalbani Group Title
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    yes...

    • 2 years ago
  10. princeofwetlot Group Title
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    now like i said f(x) = f(x-1 + 1) = f(a+1) therefore f(a + 1) = (a+ 1)^2 + 3(a+1) + 5

    • 2 years ago
  11. princeofwetlot Group Title
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    oops i made a mistake o.O

    • 2 years ago
  12. princeofwetlot Group Title
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    substituting a made me confused -_-

    • 2 years ago
  13. shahzadjalbani Group Title
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    which mistake.......

    • 2 years ago
  14. shahzadjalbani Group Title
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    I am also confused ...........

    • 2 years ago
  15. princeofwetlot Group Title
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    substituting will actually make it complicated..let me start again do you get that f[(x-1) + 1] = f(x)?

    • 2 years ago
  16. shahzadjalbani Group Title
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    yes now I am clear thank you...........

    • 2 years ago
  17. princeofwetlot Group Title
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    really? lol..great

    • 2 years ago
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