anonymous
  • anonymous
what is f(x) ? if f(x-1)=x^2+3x+5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I'm not sure, but I think its (x + 1)^2 + 3(x - 1) + 5
anonymous
  • anonymous
f(x) = f[(x -1) + 1]
anonymous
  • anonymous
yup that's right @pratu043 :)

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anonymous
  • anonymous
explain @pratu043
anonymous
  • anonymous
lol look at what i wrote...f(x-1 + 1) = f(x + 0) = f(x) since f(x-1) = x^2 + 3x + 5 f(x - 1 + 1) = (x+1)^2 + 3(x+1) + 5 got the logic?
anonymous
  • anonymous
1 and 1 will be cancelled then there will f(x) I didn't get.
anonymous
  • anonymous
hmmm you get that f(x-1 + 1) = f(x) right?
anonymous
  • anonymous
now let a = x-1 f(a) = a^2 + 3a + 5 agree?
anonymous
  • anonymous
yes...
anonymous
  • anonymous
now like i said f(x) = f(x-1 + 1) = f(a+1) therefore f(a + 1) = (a+ 1)^2 + 3(a+1) + 5
anonymous
  • anonymous
oops i made a mistake o.O
anonymous
  • anonymous
substituting a made me confused -_-
anonymous
  • anonymous
which mistake.......
anonymous
  • anonymous
I am also confused ...........
anonymous
  • anonymous
substituting will actually make it complicated..let me start again do you get that f[(x-1) + 1] = f(x)?
anonymous
  • anonymous
yes now I am clear thank you...........
anonymous
  • anonymous
really? lol..great

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