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shahzadjalbani

  • 3 years ago

what is f(x) ? if f(x-1)=x^2+3x+5

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  1. pratu043
    • 3 years ago
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    I'm not sure, but I think its (x + 1)^2 + 3(x - 1) + 5

  2. princeofwetlot
    • 3 years ago
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    f(x) = f[(x -1) + 1]

  3. princeofwetlot
    • 3 years ago
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    yup that's right @pratu043 :)

  4. shahzadjalbani
    • 3 years ago
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    explain @pratu043

  5. princeofwetlot
    • 3 years ago
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    lol look at what i wrote...f(x-1 + 1) = f(x + 0) = f(x) since f(x-1) = x^2 + 3x + 5 f(x - 1 + 1) = (x+1)^2 + 3(x+1) + 5 got the logic?

  6. shahzadjalbani
    • 3 years ago
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    1 and 1 will be cancelled then there will f(x) I didn't get.

  7. princeofwetlot
    • 3 years ago
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    hmmm you get that f(x-1 + 1) = f(x) right?

  8. princeofwetlot
    • 3 years ago
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    now let a = x-1 f(a) = a^2 + 3a + 5 agree?

  9. shahzadjalbani
    • 3 years ago
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    yes...

  10. princeofwetlot
    • 3 years ago
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    now like i said f(x) = f(x-1 + 1) = f(a+1) therefore f(a + 1) = (a+ 1)^2 + 3(a+1) + 5

  11. princeofwetlot
    • 3 years ago
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    oops i made a mistake o.O

  12. princeofwetlot
    • 3 years ago
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    substituting a made me confused -_-

  13. shahzadjalbani
    • 3 years ago
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    which mistake.......

  14. shahzadjalbani
    • 3 years ago
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    I am also confused ...........

  15. princeofwetlot
    • 3 years ago
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    substituting will actually make it complicated..let me start again do you get that f[(x-1) + 1] = f(x)?

  16. shahzadjalbani
    • 3 years ago
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    yes now I am clear thank you...........

  17. princeofwetlot
    • 3 years ago
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    really? lol..great

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