shahzadjalbani
what is f(x) ?
if f(x1)=x^2+3x+5



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pratu043
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I'm not sure, but I think its (x + 1)^2 + 3(x  1) + 5

princeofwetlot
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f(x) = f[(x 1) + 1]

princeofwetlot
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yup that's right @pratu043 :)

shahzadjalbani
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explain @pratu043

princeofwetlot
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lol look at what i wrote...f(x1 + 1) = f(x + 0) = f(x)
since f(x1) = x^2 + 3x + 5
f(x  1 + 1) = (x+1)^2 + 3(x+1) + 5
got the logic?

shahzadjalbani
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1 and 1 will be cancelled then there will f(x) I didn't get.

princeofwetlot
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hmmm you get that f(x1 + 1) = f(x) right?

princeofwetlot
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now let a = x1
f(a) = a^2 + 3a + 5
agree?

shahzadjalbani
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yes...

princeofwetlot
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now like i said f(x) = f(x1 + 1) = f(a+1)
therefore
f(a + 1) = (a+ 1)^2 + 3(a+1) + 5

princeofwetlot
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oops i made a mistake o.O

princeofwetlot
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substituting a made me confused _

shahzadjalbani
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which mistake.......

shahzadjalbani
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I am also confused ...........

princeofwetlot
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substituting will actually make it complicated..let me start again
do you get that f[(x1) + 1] = f(x)?

shahzadjalbani
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yes now I am clear thank you...........

princeofwetlot
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really? lol..great