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.Sam.

Math Quiz: A country currency consists of the following coins 1¢, 2¢, 5¢, 10¢, 25¢, 50¢. What is the most money you can have in coins and not be able to pay exactly $1? It can be over a dollar

  • one year ago
  • one year ago

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  1. FoolForMath
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    Coin change problem.

    • one year ago
  2. UnkleRhaukus
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    i guess you could have 99 1¢ pieces

    • one year ago
  3. Limitless
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    This doesn't seem well-posed.

    • one year ago
  4. .Sam.
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    It can be over a dollar

    • one year ago
  5. Limitless
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    Then.. There is no limit on what you can pay.

    • one year ago
  6. Limitless
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    Or perhaps I am not understanding correctly. You can have \(100\) 1 cent pieces, \(1000\) 1 cent pieces, \(10,000\) 1 cent pieces etc.

    • one year ago
  7. UnkleRhaukus
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    one 50¢ and three 20¢ maybe

    • one year ago
  8. Limitless
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    OH. I completely misread the sentence. My bad, yo.

    • one year ago
  9. lgbasallote
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    ohhh pop quiz *_*

    • one year ago
  10. vanihba
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    you can't hv 2 50's, 4 25's, 1 50's and 2 25's, 1 50's and 5 10's, 1 50 and 20 5's and so on....

    • one year ago
  11. UnkleRhaukus
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    oh there are no 20¢ s only 25¢

    • one year ago
  12. UnkleRhaukus
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    3×25¢ and 3×10¢ =$1.05

    • one year ago
  13. UnkleRhaukus
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    *+4¢

    • one year ago
  14. UnkleRhaukus
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    $1.09

    • one year ago
  15. vanihba
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    ans. is 124 cents?

    • one year ago
  16. .Sam.
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    @UnkleRhaukus nope :) , Hint: its greater than that

    • one year ago
  17. Limitless
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    50, 25, {10,10,10,10,10,10,10,10,10}, 5, {2,2} ?

    • one year ago
  18. Limitless
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    oops, nope.

    • one year ago
  19. RolyPoly
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    First at most 1 50 cents, since 2 50 cents coins = $1 => $0.5 Then, at most 1 25 cents coin , since 2 25 cents coins = $0.5 => + 0.5 above = 1 (=> rejected) Now, we've got $0.75 We can at most 4 $0.1 coins. since 5 x $ 0.1 = $ 0.5 + 0.5 above = $1 (=> rejected) Now, we have $ 0.75 + $ 0.4 = 1.15 We CAN'T have $0.05 coin, since it 0.05 + 0.75 = 0.8 + 0.2 = 1 (=> rejected) we can have at most 4$0.02 coins, since 5x^0.02 = $0.1 and 0.1+ 0.4 = 0.5 (rejected) Now we have 1.23 No 0.01 ... 1.23?

    • one year ago
  20. .Sam.
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    @RolyPoly is correct :D

    • one year ago
  21. RolyPoly
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    Yay!!!~

    • one year ago
  22. vanihba
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    50,25, 10, 10,10,10,2,2,2,2? oops 123

    • one year ago
  23. RolyPoly
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    *No 0.01 since 0.01 + 0.02 + 0.02 = 0.05, that is similar to 0.05 case (=> rejected)

    • one year ago
  24. Limitless
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    Thanks for the nice problem, .Sam.

    • one year ago
  25. .Sam.
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    np :)

    • one year ago
  26. RolyPoly
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    typo: we can have at most 4$0.02 coins, since 5 x 0.02 = $0.1 and 0.1+ 0.4 = 0.5 (rejected)

    • one year ago
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