.Sam.
Math Quiz:
A country currency consists of the following coins 1¢, 2¢, 5¢, 10¢, 25¢, 50¢. What is the most money you can have in coins and not be able to pay exactly $1?
It can be over a dollar
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FoolForMath
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Coin change problem.
UnkleRhaukus
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i guess you could have 99 1¢ pieces
Limitless
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This doesn't seem well-posed.
.Sam.
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It can be over a dollar
Limitless
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Then.. There is no limit on what you can pay.
Limitless
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Or perhaps I am not understanding correctly. You can have \(100\) 1 cent pieces, \(1000\) 1 cent pieces, \(10,000\) 1 cent pieces etc.
UnkleRhaukus
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one 50¢ and three 20¢ maybe
Limitless
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OH. I completely misread the sentence. My bad, yo.
lgbasallote
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ohhh pop quiz *_*
vanihba
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you can't hv 2 50's, 4 25's, 1 50's and 2 25's, 1 50's and 5 10's, 1 50 and 20 5's and so on....
UnkleRhaukus
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oh there are no 20¢ s only 25¢
UnkleRhaukus
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3×25¢ and 3×10¢ =$1.05
UnkleRhaukus
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*+4¢
UnkleRhaukus
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$1.09
vanihba
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ans. is 124 cents?
.Sam.
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@UnkleRhaukus nope :) , Hint: its greater than that
Limitless
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50, 25, {10,10,10,10,10,10,10,10,10}, 5, {2,2}
?
Limitless
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oops, nope.
RolyPoly
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First at most 1 50 cents, since 2 50 cents coins = $1 => $0.5
Then, at most 1 25 cents coin , since 2 25 cents coins = $0.5 => + 0.5 above = 1 (=> rejected)
Now, we've got $0.75
We can at most 4 $0.1 coins. since 5 x $ 0.1 = $ 0.5 + 0.5 above = $1 (=> rejected)
Now, we have $ 0.75 + $ 0.4 = 1.15
We CAN'T have $0.05 coin, since it 0.05 + 0.75 = 0.8 + 0.2 = 1 (=> rejected)
we can have at most 4$0.02 coins, since 5x^0.02 = $0.1 and 0.1+ 0.4 = 0.5 (rejected)
Now we have 1.23
No 0.01 ...
1.23?
.Sam.
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@RolyPoly is correct :D
RolyPoly
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Yay!!!~
vanihba
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50,25, 10, 10,10,10,2,2,2,2? oops 123
RolyPoly
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*No 0.01 since 0.01 + 0.02 + 0.02 = 0.05, that is similar to 0.05 case (=> rejected)
Limitless
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Thanks for the nice problem, .Sam.
.Sam.
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np :)
RolyPoly
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typo:
we can have at most 4$0.02 coins, since 5 x 0.02 = $0.1 and 0.1+ 0.4 = 0.5 (rejected)