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Math Quiz:
A country currency consists of the following coins 1¢, 2¢, 5¢, 10¢, 25¢, 50¢. What is the most money you can have in coins and not be able to pay exactly $1?
It can be over a dollar
 one year ago
 one year ago
Math Quiz: A country currency consists of the following coins 1¢, 2¢, 5¢, 10¢, 25¢, 50¢. What is the most money you can have in coins and not be able to pay exactly $1? It can be over a dollar
 one year ago
 one year ago

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FoolForMathBest ResponseYou've already chosen the best response.0
Coin change problem.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
i guess you could have 99 1¢ pieces
 one year ago

LimitlessBest ResponseYou've already chosen the best response.0
This doesn't seem wellposed.
 one year ago

LimitlessBest ResponseYou've already chosen the best response.0
Then.. There is no limit on what you can pay.
 one year ago

LimitlessBest ResponseYou've already chosen the best response.0
Or perhaps I am not understanding correctly. You can have \(100\) 1 cent pieces, \(1000\) 1 cent pieces, \(10,000\) 1 cent pieces etc.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
one 50¢ and three 20¢ maybe
 one year ago

LimitlessBest ResponseYou've already chosen the best response.0
OH. I completely misread the sentence. My bad, yo.
 one year ago

vanihbaBest ResponseYou've already chosen the best response.0
you can't hv 2 50's, 4 25's, 1 50's and 2 25's, 1 50's and 5 10's, 1 50 and 20 5's and so on....
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
oh there are no 20¢ s only 25¢
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
3×25¢ and 3×10¢ =$1.05
 one year ago

.Sam.Best ResponseYou've already chosen the best response.1
@UnkleRhaukus nope :) , Hint: its greater than that
 one year ago

LimitlessBest ResponseYou've already chosen the best response.0
50, 25, {10,10,10,10,10,10,10,10,10}, 5, {2,2} ?
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.4
First at most 1 50 cents, since 2 50 cents coins = $1 => $0.5 Then, at most 1 25 cents coin , since 2 25 cents coins = $0.5 => + 0.5 above = 1 (=> rejected) Now, we've got $0.75 We can at most 4 $0.1 coins. since 5 x $ 0.1 = $ 0.5 + 0.5 above = $1 (=> rejected) Now, we have $ 0.75 + $ 0.4 = 1.15 We CAN'T have $0.05 coin, since it 0.05 + 0.75 = 0.8 + 0.2 = 1 (=> rejected) we can have at most 4$0.02 coins, since 5x^0.02 = $0.1 and 0.1+ 0.4 = 0.5 (rejected) Now we have 1.23 No 0.01 ... 1.23?
 one year ago

vanihbaBest ResponseYou've already chosen the best response.0
50,25, 10, 10,10,10,2,2,2,2? oops 123
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.4
*No 0.01 since 0.01 + 0.02 + 0.02 = 0.05, that is similar to 0.05 case (=> rejected)
 one year ago

LimitlessBest ResponseYou've already chosen the best response.0
Thanks for the nice problem, .Sam.
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.4
typo: we can have at most 4$0.02 coins, since 5 x 0.02 = $0.1 and 0.1+ 0.4 = 0.5 (rejected)
 one year ago
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