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Coin change problem.

i guess you could have 99 1¢ pieces

This doesn't seem well-posed.

It can be over a dollar

Then.. There is no limit on what you can pay.

one 50¢ and three 20¢ maybe

OH. I completely misread the sentence. My bad, yo.

ohhh pop quiz *_*

you can't hv 2 50's, 4 25's, 1 50's and 2 25's, 1 50's and 5 10's, 1 50 and 20 5's and so on....

oh there are no 20¢ s only 25¢

3×25¢ and 3×10¢ =$1.05

*+4¢

$1.09

ans. is 124 cents?

@UnkleRhaukus nope :) , Hint: its greater than that

50, 25, {10,10,10,10,10,10,10,10,10}, 5, {2,2}
?

oops, nope.

Yay!!!~

50,25, 10, 10,10,10,2,2,2,2? oops 123

*No 0.01 since 0.01 + 0.02 + 0.02 = 0.05, that is similar to 0.05 case (=> rejected)

Thanks for the nice problem, .Sam.

np :)

typo:
we can have at most 4$0.02 coins, since 5 x 0.02 = $0.1 and 0.1+ 0.4 = 0.5 (rejected)