Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

How do I solve this? The ratio of the areas of two similar polygons is 49:16. If the perimeter of the first polygon is 22 cm, what is the perimeter of the second polygon?

Physics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

If these are regular polygons, then the question involves some manipulation of the equation: \[Area = (s^{2}*N)/(4 \tan (180/N))\] where s = the length of a side, and N = the number of sides. Since we're assuming the polygon is regular, the perimeter can be represented by the following equation: p = sN. Set up a ratio of areas (e.g Area1/ Area2 = 49/16) and the denominators cancel. You're left with \[Area_1/Area_2 = ( p^2_1N )(p^2_2N)\]. The "N"s cancel, and you get an equation relating area and perimeter for *regular* polygons. I hope you can take it from there.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question