Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

elizabethann509

  • 3 years ago

How do I solve this? The ratio of the areas of two similar polygons is 49:16. If the perimeter of the first polygon is 22 cm, what is the perimeter of the second polygon?

  • This Question is Closed
  1. happytreefriend7
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If these are regular polygons, then the question involves some manipulation of the equation: \[Area = (s^{2}*N)/(4 \tan (180/N))\] where s = the length of a side, and N = the number of sides. Since we're assuming the polygon is regular, the perimeter can be represented by the following equation: p = sN. Set up a ratio of areas (e.g Area1/ Area2 = 49/16) and the denominators cancel. You're left with \[Area_1/Area_2 = ( p^2_1N )(p^2_2N)\]. The "N"s cancel, and you get an equation relating area and perimeter for *regular* polygons. I hope you can take it from there.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy