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anonymous
 3 years ago
Prove that the sum of n harmonic numbers H_1 + H_2 + ... + H_n = (n+1)H_n  n
anonymous
 3 years ago
Prove that the sum of n harmonic numbers H_1 + H_2 + ... + H_n = (n+1)H_n  n

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do you define as a harmonic number? \(H_n= \frac{1}{n}\)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0H_n =1+ 1/2 + 1/3 + ... 1/n

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0H_n is the actual sum from k=1 to n of 1/k

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So: \[H_n=\sum_{1 \leq i \leq n}\frac{1}{i}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Have you read Concrete Mathematics?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No, I'm in a Discrete Mathematics course right now. This is one of the challenge homework problems in the book.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Concrete Mathematics has an entire chapter dedicated to summation. You could learn various great concepts. This is even one particular problem. I recommend the book to you. I could attempt to explain the method, if you would like. It is a weebit complex, however.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I guess you could try.. the course assumes the student has a math background up to Calculus I. So far I've completed three calculus courses, ordinary differential equations, and linear algebra. Not sure if this problem pulls material from these latter courses though. Even so I doubt I'll understand what you're about to explain lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But basically, a summation of a summation, right? Although I don't think the way to approach that is basic at all haha

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, that is step one. It requires manipulating the sum from there.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{j=1}^{n} H_n = \sum_{j=1}^{n} \sum_{k=1}^{j} \frac{1}{k}\] Lol, what's next?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait, first. Do you know what the Iverson Bracket is?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0idk if I even typed that right.. aside from indexing errors

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's okay. Not many people do. But it is a notation used in summation to make things easier. The idea is this: \[ [x]= \left\{ \begin{array}{c} 1 &\text{if } x \text{ is true},\\ 0 &\text{otherwise.} \end{array} \right. \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, so this is relevant because it allows summation to be manipulated easily. When we say, for example, \(\sum_{1 \leq i \leq n}i\), we can equivalently say (using this notation) \[\sum_{i} i [1\leq i \leq n]\] This works because we take \(i\) to be evaluated from \(\infty\) to \(\infty\) and the Iverson Bracket is zero at all points which do not satisfy our condition. Make sense?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(Oh, by the way, \(\sum_{1 \leq i \leq n}i\) is the same as \(\sum_{i=1}^{n}i\).)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0actually.. we may actually be able to prove it without using that. the chapter I'm working on is about proofs by induction. a simple algebraic manipulation may work

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ah, yes. Induction is much easier. But this makes sense of _why_ it is how it is.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0For induction, check \(n=1\). Then, assume for some integer \(k\), that the statement is true. Show that by adding \(H_{k+1}\) to the left side results in the right side.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Haha thanks.. Sorry for the trouble. Maybe I should've mentioned induction earlier

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No, it's fine. You should learn about Iverson Brackets and etc anyway. Trust me, it makes almost every summation ridiculously easier.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks, that might help in later computer science classes. The course I'm taking right now is like discrete math for comp sci

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Concrete Mathematics is all about Discrete Mathematics. Take a look here on Wiki about it: http://en.wikipedia.org/wiki/Concrete_Mathematics

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh wow, then I might really come across it in my later years of study. Thank you very much for the info!
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